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allsm [11]
3 years ago
5

GIVEN BRAINLIEST

Chemistry
1 answer:
umka21 [38]3 years ago
6 0

Answer:

A. your observations in writing

Explanation:

Descriptive investigation is one of the mode of inquiries in science. It is devoid of the usual collection of data in the field or setting up laboratory experiments to compared variables.

  • In descriptive investigation, observations are usually done in writing.
  • They are usually common in Astrology.
  • Such investigation involves a question without a hypothesis ensuing.
  • Tests are usually not carried out in descriptive investigation.
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A 500.0 mL sample of 0.18 MHClO4 is titrated with 0.27 MCsOH. Determine the pH of the solution after the addition of 250.0 mL of
NNADVOKAT [17]

Answer:

or i go

Explanation:

i must go ooon sjsj

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2 years ago
How is 0.00069 written in scientific notation?
vfiekz [6]
6.9 x 10^-4 would be .00069 written in scientific notation
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3 years ago
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The least polar bond is found in a molecule of hi hf hcl hbr
mario62 [17]

Answer:

HI is least polar

Explanation:

5 0
3 years ago
The weight of a sack potato in india is 50kgf. will the weight increase or decrease in bhutan. why​
AfilCa [17]

Answer:

Assume that the sack was initially close to the sea level. Its weight will increase even though its mass stays the same.

Explanation:

The weight of an object typically refers to the size of the planet's gravitational attraction (a force) on this object. That's not the same as the mass of the object. The weight of an object at a position depends on the size of the gravitational field there; on the other hand, the mass of the object is supposed to be same regardless of the location- as long as the object stays intact.

Let g denote the strength of the gravitational field at a certain point. If the mass of an object is m, its weight at that point will be m \cdot g.

Indeed, g \approx 9.81\; \rm N \cdot kg^{-1} on many places of the earth. However, this value is accurate only near the sea level. The equation for universal gravitation is a more general way for finding the strength of the gravitational field at an arbitrary height. Let G denote the constant of universal gravitation, and let M denote the mass of the earth. At a distance r from the center of the earth (where

\displaystyle g \approx \frac{G \cdot M}{r^2}.

The elevation of many places in Bhutan are significantly higher than that of many places in India. Therefore, a sack of potato in Bhutan will likely be further away from the center of the earth (larger r) compared to a sack of potato in India.

Note, that in the approximation, the value of g is (approximately, because the earth isn't perfectly spherical) inversely proportional to the distance from the center of the planet. The gravitational field strength

On the other hand, the weight of an object of fixed mass is proportional to the gravitational field strength. Therefore, the same bag of potatoes will have a smaller weight at most places in Bhutan compared to most places in India.

6 0
3 years ago
If the pressure inside the cylinder increases to 1.3 atm, what is the final
EleoNora [17]

Answer:

1.4 × 10² mL

Explanation:

There is some info missing. I looked at the question online.

<em>The air in a cylinder with a piston has a volume of 215 mL and a pressure of 625 mmHg. If the pressure inside the cylinder increases to 1.3 atm, what is the final volume, in milliliters, of the cylinder?</em>

Step 1: Given data

  • Initial volume (V₁): 215 mL
  • Initial pressure (P₁): 625 mmHg
  • Final volume (V₂): ?
  • Final pressure (P₂): 1.3 atm

Step 2: Convert 625 mmHg to atm

We will use the conversion factor 1 atm = 760 mmHg.

625 mmHg × 1 atm/760 mmHg = 0.822 atm

Step 3: Calculate the final volume of the air

Assuming constant temperature and ideal behavior, we can calculate the final volume of the air using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 0.822 atm × 215 mL / 1.3 atm = 1.4 × 10² mL

5 0
3 years ago
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