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allsm [11]
3 years ago
5

GIVEN BRAINLIEST

Chemistry
1 answer:
umka21 [38]3 years ago
6 0

Answer:

A. your observations in writing

Explanation:

Descriptive investigation is one of the mode of inquiries in science. It is devoid of the usual collection of data in the field or setting up laboratory experiments to compared variables.

  • In descriptive investigation, observations are usually done in writing.
  • They are usually common in Astrology.
  • Such investigation involves a question without a hypothesis ensuing.
  • Tests are usually not carried out in descriptive investigation.
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What is science......?​
den301095 [7]

\huge \underbrace \mathfrak \blue{Answer}

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3 years ago
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Zinc phosphide, Zn3P2, is often used as a rat poison. Phosphorus has 5 valence electrons. How many valence electrons does each z
Helen [10]
The choices that should have accompanied this question were:
A. 1 
<span>B. 2 </span>
<span>C. 3 </span>
<span>D. 4 
</span>
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Below is an explanation, I found while doing the research.

<span>Phosphate needs 3 electrons each totaling 6 electrons so each zinc will need to give up 2 electrons.

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3 years ago
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What r rocks made of
Iteru [2.4K]
Most are made from crystals and minerals.
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3 years ago
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How many moles of carbon are in 3.5 L?
SashulF [63]

Answer:

0.16mole

Explanation:

To solve this problem, we are going to assume that the number of moles of carbon to be determined is that at STP, standard temperature and pressure.

The number of moles of a substance at STP is given as;

 Number of moles  = \frac{volume}{22.4}  

Given volume  = 3.5L

Now, insert the parameters;

     Number of moles  = \frac{3.5}{22.4}   = 0.16mole

8 0
3 years ago
1 How many moles of solute are in:
Sonbull [250]

Moles of solute for both a and b are the same = 1 mol

<h3>Further explanation</h3>

Given

a 500 cm³ of solution, of concentration 2 mol/dm³

b 2 litres of solution, of concentration 0.5 mol/dm³

Required

moles of solute

Solution

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

Can be formulated :

\large \boxed {\bold {M ~ = ~ \dfrac {n} {V}}}

a.

V = 500 cm³ = 0.5 L

M = 2 mol/L

n=moles = M x V

n = 2 mol/L x 0.5 L

n = 1 mol

b.  

V = 2 L

M = 0.5 mol/L

n=moles = M x V

n = 0.5 mol/L x 2 L

n = 1 mol

5 0
3 years ago
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