Step-by-step explanation:
Part A: The temperature must be greater than -40, and lower than 140. -40 < T < 140
Part B: The graph is a number line between -40 and 140, with open circles at -40 and 140. The solutions are temperatures at which the gas will remain liquid.
Part C: No, -49 is less than -40, so the gas would have frozen.
Given:
m∠APB = 19°
To find:
The arc measure of DBC.
Solution:
∠APB and ∠DPC are vertical angles.
By vertical angle theorem:
m∠APB = m∠DPC
m∠DPC = 19°
DB is the diameter of the circle.
Angle measure of diameter = 180°
m∠DPB = 180°
m∠DPC + m∠CPB = m∠DPB
19° + m∠CPB = 180°
Subtract 19° from both sides.
19° + m∠CPB - 19° = 180° - 19°
m∠CPB = 161°
<em>The measure of central angle is equal to the measure of intercepted arc.</em>
m∠CPB = m(ar CPB)
m(ar CPB) = 161°
The arc measure of DBC is 161°.
-0.2
'0
-0.2 = - .2 = - 2/10 = - 1/5
so
answer is -1/5
I think you’re correct. It’s B. But the answer D is literally the same as B, so is there a “both B and D” option?