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Travka [436]
3 years ago
7

Measure the diameter of the quarter to the nearest eighth of an inch. (Hint: The diameter is the length of the quarter, going th

rough the center.)
Measure the diameter of the quarter to the nearest eighth of an inch. (Hint: The diameter is the length of the quarter, going through the center.)









1\2 inch
5\8 inch
3\4 inch
7\8 inch

Mathematics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

5/8

Step-by-step explanation:

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What does OD=<br> Pls answer
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Step-by-step explanation:

We can draw a line from O to B to create a triangle.

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Now relating the corresponding sides, we can figure out OD:

\frac{OD}{DB}=\frac{AC}{CB}\\\frac{OD}{8-3}=\frac{15}{8}\\\frac{OD}{5}=\frac{15}{8}\\8OD=5*15\\OD=\frac{5*15}{8}\\OD=9.375

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The histogram below displays the distribution of 50 ages at death due to trauma (unnatural accidents and homicides) that were ob
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d. The median and the IQR

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The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median. This means that the median is the appropriate numerical measure to describe the center.

The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.

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The interquartile range(IQR), is Q3-Q1.

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d. The median and the IQR

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