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zloy xaker [14]
3 years ago
9

Solve for x I need help for this question

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
8 0

Answer:

23⁰

Step-by-step explanation:

that being a right angle means the angles add up to 90⁰. make an equation in respect to X (90= 63+x-4) collect like terms together and solve for x

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Find the value of x given that the mean is 6:<br><br> 2, 8, 9, 7, 6, x
Novosadov [1.4K]

Answer:

4

Step-by-step explanation:

(32 + x)/6=6

8 0
4 years ago
Nina has $5 and $10 bills in her wallet. She has a total of 13 bills with a value of $85. How many of each type of bill does she
matrenka [14]

Answer:

I got eleven 5 dollar bills and and I got 3 ten dollar bills

Step-by-step explanation:

what i did was start out with 85/5, then that was 17 so I started minusing 2 fives to = 1 ten so 15 5's and 1, 10 then so forth 13 5 dollar bills and 2 10 dollar bills, 11 5 dollar bills and 3 ten dollar bills. y=-2x+17

5 0
2 years ago
A girl’s club held a fundraiser last year and raised $600 for the local soup kitchen. This year they raised $960. What is the pe
KatRina [158]
960-600 = $360

360/600 x 100%
6 / 10 x 100%
60%
5 0
4 years ago
Please help me thanks
BabaBlast [244]

Answer:

16.7

Step-by-step explanation:

We can use the Pythagorean theorem, a^2 + b^2 = c^2.

a = 11

c = 20

11^2 + b^2 = 20^2

121 + b^2 = 400

b^2 = 279

b = sqrt(279) = 16.7

5 0
3 years ago
How many "words" can be written using exactly five A's and no more than three B's (and no other letters)?
kakasveta [241]

This is a problem of Permutations. We have 3 cases depending on the number of B's. Since no more than three B's can be used we can use either one, two or three B's at a time.

Case 1: Five A's and One B

Total number of letters = 6

Total number of words possible = \frac{6!}{5!*1!}=6

Case 2: Five A's and Two B's

Total number of letters = 7

Total number of words possible = \frac{7!}{5!*2!}=21

Case 3: Five A's and Three B's

Total number of letters = 8

Total number of words possible = \frac{8!}{5!*3!}=56

Total number of possible words will be the sum of all three cases.

Therefore, the total number of words that can be written using exactly five A's and no more than three B's (and no other letters) are 6 + 21 + 56 = 83

8 0
4 years ago
Read 2 more answers
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