I guess you need solution on C++. Here is the code:
int main () { double areaofsquare; double length cin >> areaofsquare;
<span>length = sqrt(areaOfSquare);
std::cout << length << std::endl;</span> if(areaofsquare >= 0) { sqrt(areaofsquare); cout << areaofsquare << endl; } else { cout << "INVALID" << endl; }
}
Answer: abstract algebra
Explanation: start with the algorithm you are using, and phrase it using words that are easily transcribed into computer instructions.
Indent when you are enclosing instructions within a loop or a conditional clause. ...
Avoid words associated with a certain kind of computer language.
<span>Quebec and British; French and Indian War</span>
Answer:
z = a.c' + a.b.d' + b.c'.d'
Explanation:
The truth table for this question is provided in the attachment to this question.
N.B - a' = not a!
The rows with output of 1 come from the following relations: 01 > 00, 10 > 00, 10 > 01, 11 > 00, 11 > 01, 11 > 10
This means that the Boolean expression is a sum of all the rows with output of 1.
z = a'bc'd' + ab'c'd' + ab'c'd + abc'd' + abc'd + abcd'
On simplification,
z = bc'd' + ab'c' + ac'd' + ac'd + abc' + abd'
z = ac' + abd' + bc'd'
Hope this helps!