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Anastasy [175]
3 years ago
13

What was designed as an area where computer vendors could store data that is shielded from user activities and operating system

utilities, such as delete and format
Computers and Technology
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

host protected area

Explanation:

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Edhesive lesson practice 8.3, question 5
scZoUnD [109]

Answer:

3

Explanation:

8 0
3 years ago
Given a double variable named areaofsquare write the necessary code to read in a value , the area of some square, into areaofsqu
kifflom [539]
I guess you need solution on C++. Here is the code:

int main () {    double areaofsquare;    double length    cin >> areaofsquare;
<span>length = sqrt(areaOfSquare);
 
std::cout << length << std::endl;</span>       if(areaofsquare >= 0)    {     sqrt(areaofsquare);     cout << areaofsquare << endl;          }      else     { cout << "INVALID" << endl;              } 
      }
6 0
3 years ago
PLzzzzzz help me!! I will mark brainiest to the one who answers it right!!
jasenka [17]

Answer: abstract algebra

Explanation: start with the algorithm you are using, and phrase it using words that are easily transcribed into computer instructions.

Indent when you are enclosing instructions within a loop or a conditional clause. ...

Avoid words associated with a certain kind of computer language.

4 0
3 years ago
What natural boundary separated british territory from louisiana?
Marat540 [252]
<span>Quebec and British; French and Indian War</span>
4 0
3 years ago
Given four inputs: a, b, c &amp; d, where (a, b) represents a 2-bit unsigned binary number X; and (c, d) represents a 2-bit unsi
Amiraneli [1.4K]

Answer:

z = a.c' + a.b.d' + b.c'.d'

Explanation:

The truth table for this question is provided in the attachment to this question.

N.B - a' = not a!

The rows with output of 1 come from the following relations: 01 > 00, 10 > 00, 10 > 01, 11 > 00, 11 > 01, 11 > 10

This means that the Boolean expression is a sum of all the rows with output of 1.

z = a'bc'd' + ab'c'd' + ab'c'd + abc'd' + abc'd + abcd'

On simplification,

z = bc'd' + ab'c' + ac'd' + ac'd + abc' + abd'

z = ac' + abd' + bc'd'

Hope this helps!

6 0
4 years ago
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