9514 1404 393
Answer:
Step-by-step explanation:
Let a and s represent the prices of adult and student tickets, respectively.
13a +12s = 211 . . . . . . ticket sales the first day
5a +3s = 65 . . . . . . . ticket sales the second day
Subtracting the first equation from 4 times the second gives ...
4(5a +3s) -(13a +12s) = 4(65) -(211)
7a = 49 . . . . . . . simplify
a = 7 . . . . . . . divide by 7
5(7) +3s = 65 . . . . substitute into the second equation
3s = 30 . . . . . . . subtract 35
s = 10 . . . . . . . divide by 3
The price of one adult ticket is $7; the price of one student ticket is $10.
Answer:
It's below in the explanation
Explanation
1. x has to be greater than 2. So 3 and 4 both work
2. x has to be less than 22. So 21 and 20 both work
3. t has to be less than 5. So 3 and 4 both work
4. There isn't a number there. what is 5 less that?
5. j has to be less than 5 so 5 and 4 both work
6. y has to be less than 4. So 4 and 3 both work
7. B has to be greater than 26. so 26 27 and 28 all work
8.There isn't a number there
9.b can be 3 or greater than 3.
10.z can be 6 or greater than 6
Hope this Helps!
Let's actually find the roots, using the quadratic formula:
<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.
-1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------
2
The discriminant here is negative, so the roots x will be complex:
-1 plus or minus sqrt(-11) -1 plus or minus i*sqrt(11)
x = ---------------------------------- = -------------------------------------
2 2
These are irrational roots; they cannot be expressed as the ratios of integers.</span>
Yes they are equivalent. You get -3 when you try solving the actual equation.
Answer:
0
Step-by-step explanation:
Use two-point form to find the slope.
m=y2-y1/x2-x1
m=0-0/10-5
m=0/5
