The height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.
<h3>Pressure and temperature at equilibrium </h3>
The relationship between pressure and temperature can be used to determine the height risen by the water.
where;
- V₁ = AL
- V₂ = A(L - y)
- P₁ = Pa
- P₂ = Pa + ρgh
- T₁ = 20⁰C = 293 K
- T₂ = 10⁰ C = 283 k
Thus, the height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.
The complete question is below:
A diving bell is a 4.2 m -tall cylinder closed at the upper end but open at the lower end. The temperature of the air in the bell is 20 °C. The bell is lowered into the ocean until its lower end is 100 m deep. The temperature at that depth is 10°C. How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium?
Learn more about thermal equilibrium here: brainly.com/question/9459470
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Answer:
Gravity as well as electrostatic and magnetic attraction and repulsion provide real life examples of forces being exerted by one object on another without them being in contact with each other.
Explanation:
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Answer:
V2 = 15.53 [m/s]]
Explanation:
In order to solve this problem we must use the principle of energy conservation, where potential energy is transformed into kinetic energy. At the bottom is taken as a reference level of potential energy, where the value of this energy is equal to zero.
Above the inclined plane we have two energies, kinetics and potential. While when the sled is at the reference level all this energy will have been transformed into kinetic energy.
![E_{1}=E_{2}\\ m*g*h+(\frac{1}{2} )*m*v_{1} ^{2}=\frac{1}{2}*m*v_{2} ^{2} \\(9.81*8.21)+(0.5*8.96^{2} )=(0.5*v_{2}^{2} )\\(0.5*v_{2}^{2} )=120.68\\v_{2} ^{2}=241.36\\v_{2} =\sqrt{241.36}\\ v_{2} =15.53[m/s]](https://tex.z-dn.net/?f=E_%7B1%7D%3DE_%7B2%7D%5C%5C%20%20m%2Ag%2Ah%2B%28%5Cfrac%7B1%7D%7B2%7D%20%29%2Am%2Av_%7B1%7D%20%5E%7B2%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av_%7B2%7D%20%5E%7B2%7D%20%5C%5C%289.81%2A8.21%29%2B%280.5%2A8.96%5E%7B2%7D%20%29%3D%280.5%2Av_%7B2%7D%5E%7B2%7D%20%29%5C%5C%280.5%2Av_%7B2%7D%5E%7B2%7D%20%29%3D120.68%5C%5Cv_%7B2%7D%20%5E%7B2%7D%3D241.36%5C%5Cv_%7B2%7D%20%3D%5Csqrt%7B241.36%7D%5C%5C%20%20v_%7B2%7D%20%3D15.53%5Bm%2Fs%5D)
Answer:
When force and displacement are in the same direction, the work performed on an object is said to be positive work. Example: When a body moves on the horizontal surface, force and displacement act in the forward path. The work is done in this case known as Positive work.
Explanation:
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