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Scorpion4ik [409]
3 years ago
7

You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65mi/h), and the trip takes

2 hr and 20 min. On a Friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 70 km/h (50 mi/h). How much longer does the trip take?
Physics
2 answers:
likoan [24]3 years ago
7 0

Answer:

Given the second case mentioned, the trip will take:

  • <u>1 hour and 10 minutes more than in the first case, that is, it will take 3 hours with 30 minutes in total.</u>

Explanation:

To calculate how much longer someone will take on that journey, you must calculate the distance traveled, using the aforementioned initial speed, however, the time must be converted into a number that you can calculate, this is done using a rule of three:

  • 60 minutes = 1
  • 20 minutes = X
  • X = 20 minutes / 60 minutes = 0.33333

Now it is calculated:

  • Kilometers traveled = 105 km / h (speed used) * 2,333 hours (the change from 2 hours and twenty minutes to a number) = 245 km

Now you just need to divide the total distance by the new speed to find the total time spent now:

  • Total time case 2 = 245 Km / 70 Km / h = <u>3.5 hours</u> (which is equal to <u>3 hours and 30 minutes</u>)

Since the time of the first case was 2 hours 20 minutes, the difference is <u>1 hour 10 minutes</u>.

Paha777 [63]3 years ago
5 0

Answer:

3 hours and 28 minutes.

Explanation:

Average speed is gu=iven by,

Average speed = \frac{Total distance}{Total time}

∴ Total distance = Average speed × Total time

Average speed = 105 \frac{km}{h}

Total time = 2 hour and 20 minutes = 2.33 hour

Total distance = 105 × 2.33

Total distance = 244.65 km

The total distance between San Diego and Los Angeles is 244.65 km.

Due to heavy traffic the average speed is decreased to 70 \frac{km}{h}.

Average speed = \frac{Total distance}{Total time}

∴ Total time =  \frac{Total distance}{Average speed }

Total time = \frac{244.65}{70}

Total time = 3.495 hours

Total time = 3 hours and 28 minutes

Thus due to heavy traffic the time taken to travel from between San Diego and Los Angeles is 3 hours and 28 minutes.


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Answer:

a=2.5\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly over time.

The equation that describes the change of velocities is:

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\displaystyle a=\frac{v_f-v_o}{t}

The ball starts at rest (vo=0) and rolls down an inclined plane that makes it reach a speed of vf=7.5 m/s in t=3 seconds.

The acceleration is:

\displaystyle a=\frac{7.5-0}{3}

\boxed{a=2.5\ m/s^2}

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A catapult used by medieval armies hurls a stone of mass 32.0 kg with a velocity of 50.0 m/s at a 30.0 degree angle above the ho
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Answer:

The horizontal distance traveled when the stone returns to its original height = 220.81 m

Explanation:

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At maximum height,

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Acceleration , a = -9.81 m/s²

Final velocity, v = 0 m/s

We have equation of motion v = u + at

Substituting

    v = u + at

    0 = 25  - 9.81 x t

    t = 2.55 s

Time of flight = 2 x Time to reach maximum height = 2 x 2.55 = 3.1 s

Considering horizontal motion of catapult:-

Initial velocity, u =  50 cos30 = 43.30 m/s

Acceleration , a = 0 m/s²

Time, t = 5.10 s

We have equation of motion s= ut + 0.5 at²

Substituting

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The horizontal distance traveled when the stone returns to its original height = 220.81 m

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