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inn [45]
3 years ago
8

An object was measured by a worker as

Chemistry
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer: The percent error in the worker's measurement is 1.38%

Explanation:

Actual length of the object = 14.4 cm

length measured by the worker = 14.6 cm

absolute error in measuring the object = 14.6 - 14. 4 = 0.2 cm

percentage error =\frac{\text {absolute error}}{\text {actual length}}\times 100\%

Putting in the values we get:

percentage error =\frac{0.2}{14.4}\times 100\%=1.38\%

Thus the percent error in the worker's measurement is 1.38%

marusya05 [52]3 years ago
6 0
<h2>Answer - 0.73%</h2>

14.6            .2

          =          

100              x

(Above is proportions I used to get the answer)

x = 0.73% which is the answer.

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3 years ago
CaCO3 (s) + 176 KJ à CaO (s) + CO (g)
statuscvo [17]

Answer:

its d

Explanation:

3 0
3 years ago
50 POINTSSSSS PLZ HELPPPPPP NEED TO SHOW WORK!!!!
VashaNatasha [74]
(4 mol H2O) x (112 kJ / 3 mol H2O) = 149 kJ 

<span>(14.5 g HCl) / (36.4611 g HCl/mol) x (112 kJ / 3 mol HCl) = 14.9 kJ </span>

<span>(475 kJ) / (181 kJ / 2 mol HgO) x (216.5894 g HgO/mol) = 1137 g HgO </span>

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<span>(145 kJ) / (112 kJ / 3 mol Cl2) x (70.9064 g Cl2/mol) = 275 g Cl2 </span>

<span>(14.5 g S2Cl2) / (135.0360 g S2Cl2/mol) x (112 kJ / 1 mol S2Cl2) = 12.0 kJ </span>

<span>CaCO3 + 2 NH3 → CaCN2 + 3 H2O; ∆H = –90.0 kJ </span>
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5 0
3 years ago
How many grams of KBrO2 are there in 0.168 moles
Mnenie [13.5K]

Hey There!

Molar mass KBrO2 = 151.0011 g/mol

1 mole KBr --------- 151.0011 g

So in 0.168 moles :

mass = number of moles * molar mass

mass = 0.168 * 151.0011

mass = 25.36 g of KBrO2

5 0
3 years ago
1. Rank the following solutions in order of increasing
babunello [35]

The order of the solutions from lowest to highest concentration : A, B, C

<h3>Further explanation</h3>

Given

the following solutions

Required

order of increasing  concentration

Solution

Molarity shows the number of moles of solute in every 1 liter of solution.

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Solution A : 0.5 moles : 2 L solution = 0.25 M

Solution B : 1 moles : 3 L solution = 0.33 M

Solution C : 1.5 moles : 4 L solution = 0.375 M

8 0
3 years ago
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