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Gemiola [76]
2 years ago
6

A chemical reaction is at equilibrium when:_______.a. the reaction occurs quickly. b. there is no reverse reaction possible, onl

y a forward reaction. c. there are equal amounts of products and reactants. d. the rate of the forward reaction equals the rate of the reverse reaction.
Chemistry
1 answer:
Diano4ka-milaya [45]2 years ago
4 0

Answer: D.

Explanation: A chemical reaction is said to be in a state of equilibrium when the rate of the forward reaction equals the rate of the backward reaction, thus, there is no net change in the concentration of reactants and products.

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1.20×10−8s to nanoseconds
AveGali [126]

Answer:

There are 12 nanoseconds in 1.2\times 10^{-8}\ s.

Explanation:

We need to convert 1.2\times 10^{-8}\ s to nanoseconds.

We know that,

1\ s=10^9\ ns

Now using unitary method to solve it such that,

1.2\times 10^{-8}\ s=1.2\times 10^{-8}\ \times 10^9\\\\=1.2\times 10\\\\=12\ ns

So, there are 12 nanoseconds in 1.2\times 10^{-8}\ s.

7 0
2 years ago
21 Which process is used to determine the concentration of an acid?
Inessa05 [86]

Answer:

4) Titration

Explanation:

Titration is a common process used to determine the concentration of acids. It does this by adding a solution of base with a known concentration to the acid until it reaches neutralization.

8 0
3 years ago
20. What is the area of a piece of metal foil that measures 43.9 cm by 29.21 cm? Express the answer to
Aneli [31]

Answer:

The correct answer is b. 1280 cm^2

4 0
3 years ago
What is the mass of 5.84 × 10^21 atoms of xenon?
podryga [215]

Answer:

5.84e+21

Explanation:

8 0
2 years ago
Consider the nuclear equation below. Superscript 235 subscript 92 upper U right arrow superscript 4 subscript 2 upper H e. What
Leto [7]

Answer: The nuclide symbol of X is ^{231}_{90}\textrm{Th}

Explanation:

The given nuclear reaction is a type of alpha decay process. In this process, the nucleus decays by releasing an alpha particle. The mass number of the nucleus is reduced by 4 units and atomic number is also decreased by 2 units. The particle released is a helium nucleus.

The general equation representing alpha decay process is:

_{Z}^{A}\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\textrm{He}

For the given equation :

^{235}_{92}\textrm{U}\rightarrow ^{A}_{Z}\textrm{X}+^4_2\textrm{He}

As the atomic number and mass number must be equal on both sides of the nuclear equation:

^{235}_{92}\textrm{U}\rightarrow ^{231}_{90}\textrm{Th}+^4_2\textrm{He}

Thus the nuclide symbol of X is ^{231}_{90}\textrm{Th}

5 0
3 years ago
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