The answer is potential energy...
Hope this helped :)
Each of the configuration belongs to period and group as follows:
<span>6s2 - Lanthanide series
</span><span>Period<span>6
</span></span><span>Group 3B
3s2 - Magnesium
</span><span>Period<span>3
</span></span><span>Group 1
3p5 - Chlorine
</span>Period3
<span>Group17</span><span>
4s2 - Zinc
</span>Period4
<span>Group12</span><span>
4p2- Germanium
</span>Period4
<span>Group14
Hope this answers the question. Have a nice day.</span>
Given :
Mass of Ba(OH)₂ , m = 35.5 g.
Volume of mixture, V = 325 mL = 0.325 L.
To Find :
The molarity of a solution.
Solution :
We know, molarity of a solution is given by :
We know, molecular mass of Ba(OH)₂ is given by :
M.M. = 171 g/mol
Putting all these values in given equation, we get :
Hence, this is the required solution.
Answer:
That leaves us with: 1s2 2s2 2p6 And that is the electron configuration for F- , the Fluoride ion.
Explanation:
plz give brainliest
Answer:
LOD = 0,0177
LOQ = 0,0345
Explanation:
Detection limit (LOD) is defined as the lowest signal which, with a stated probability, can be distinguished from a suitable blank signal. In the same way, quantification limit (LOQ) is defined as the lowest analyte concentration that can be quantitatively detected with a stated accuracy and precision.
There are many formulas but the most used are:
LOD = X + 3σ
LOQ = X + 10σ
Where X is average and σ is standard desvation
For the blanks readings the average X is 0,0105 and σ is 0,0024
Thus:
<em>LOD = 0,0177</em>
<em>LOQ = 0,0345</em>
I hope it helps!
