NaHCO3 = 22.99 + 1.008 + 16(3) = 83.99 g/mol

Na = 22.99g/83.99 g weight of molecule =.2727 or 27.27%

3.0 g* .2727 = 0.8211 grams of sodium in sample of NaHCO3

0.8211 grams Na + 1.266 grams Cl = 2.087 grams

7 0

3 years ago

(c) ammonium carbonate + lead nitrate ? Step-by-step solution Step 1 of 3 v Step 2 of 3 v Step 3 of 3 ^ c) The ions formed in so

kenny6666 [7]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium carbonate and lead nitrate is given as:

$(NH_4)_2CO_3(aq.)+Pb(NO_3)_2(aq.)\rightarrow PbCO_3(s)+2NH_4NO_3(aq.)$

Ionic form of the above equation follows:

$2NH_4^+(aq.)+CO_3^{2-}(aq.)+Pb^{2+}(aq.)+2NO_3^-(aq.)\rightarrow PbCO_3(s)+2NH_4^+(aq.)+2NO_3^-(aq.)$

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Pb^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow PbCO_3(s)$

Hence, the net ionic equation is written above.

3 0

2 years ago

Do all smells travel at the same speed

mr_godi [17]

No, physics does not suggest an exact pace in which a chemical compound will travel. It will matter in external forces as well as the median it is travelling through.

7 0

2 years ago

During science lab, some students added small pieces of magnesium ribbon to 10 mL of hydrochloric acid. They noticed that bubble

stiv31 [10]

Your answer would be a change in odor! Hope this helps! ;D

4 0

3 years ago

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