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mihalych1998 [28]
3 years ago
10

2567 milliliters to liters

Chemistry
1 answer:
andrew-mc [135]3 years ago
6 0

Answer:

2.567 litres

Explanation:

I dont have a proper explanation sorry

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Answer:

Organic compounds

Explanation:

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8x10^-200 in significant figures PLEASE IVE BEEN STUCK ON IT FOR 2 HOURS
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In a chemical reaction 88g of CO2 was produced at r.t.p. <br> Calculate the volume of CO2 in dm??
Tems11 [23]

Explanation:

RFM = 44 \: g \\ 44g \: contain \: 1 \: mole \\ 88g \: will \: contain \: ( \frac{88}{44}  \times 1) \\  = 2 \: moles \\ at \: room \: temperature \\ 1 \: mole \: occupies \: 24 \:  {dm}^{3}  \\ 2 \: moles \: occupies \: (2 \times 24) \\  = 48 \:  {dm}^{3}

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3 years ago
Which pair of elements is MOST likely to chemically combine and form ionic bonds?
dsp73
The right answer for the question that is being asked and shown above is that: "C. carbon and hydrogen." The pair of elements is MOST likely to chemically combine and form ionic bonds are <span>carbon and hydrogen </span>
5 0
3 years ago
A solution is created by dissolving 13.0 grams of ammonium chloride in enough water to make 295 mL of solution. How many moles o
Masja [62]

Answer:

(a) Moles of ammonium chloride = 0.243 moles

(b) Molarity_{ammonium\ chloride}=0.824\ M

(c) 60.68 mL

Explanation:

(a) Mass of ammonium chloride = 13.0 g

Molar mass of ammonium chloride = 53.491 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{13.0\ g}{53.491\ g/mol}

<u>Moles of ammonium chloride = 0.243 moles</u>

(b) Moles of ammonium chloride = 0.243 moles

Volume = 295 mL = 0.295 L ( 1 mL = 0.001 L)

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{ammonium\ chloride}=\frac{0.243}{0.295}

Molarity_{ammonium\ chloride}=0.824\ M

(c) Moles of ammonium chloride = 0.0500 moles

Volume = ?

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Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

0.824\ M=\frac{0.0500}{Volume}

<u>Volume = 0.05 / 0.824 L = 0.06068 L = 60.68 mL</u>

6 0
4 years ago
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