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Ivenika [448]
2 years ago
7

The amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 30 and 60 minutes. The

professor wants to reward (with bonus marks) students who are in the lowest quarter of completion times. What completion time should he use for the cutoff for awarding bonus marks
Mathematics
1 answer:
Oliga [24]2 years ago
8 0

Answer:

37.5 minutes

Step-by-step explanation:

Let the amount of time it takes a student to complete a statistics quiz be = t

t is uniformly distributed between 30 minutes and 60 minutes

The professor wants to reward with bonus marks, students who are in the lowest quarter of t

<em>- What value of t should he use as the cutoff for awarding bonus marks?</em>

<em></em>

A quarter of any number is 1/4 of it.

Now, the range of t (the difference between the highest and lowest values of t) is 60 - 30 = 30

1/4 of 30 = 7.5

The lowest quarter of t is hence between 30 and 37.5

So the cutoff for awarding bonus marks is t = 37.5minutes

INTERPRETATION:

Any student who spends 37.5 minutes or below on a statistics quiz, will be awarded bonus marks.

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The blue dot is at what value on the number line? 5​
Eduardwww [97]

Answer:

value of blue dot is -6

Step-by-step explanation:

-6 is visible if you go 3 units to the left of -3. -3 - 3 = -6.

4 0
2 years ago
Please help! It will be appreciated!
AysviL [449]
It’s d, looks like you got it already! With ratios, just pay attention to not only the numbers but order of the words as well, so you can be sure the ratio follows the problem.
8 0
3 years ago
Read 2 more answers
Which is the height of the triangle?<br> ( PIC IS PROVIDE PLS HELP ME)
zysi [14]
<h3>Answer: 80 meters</h3>

This is an isosceles triangle. The dashed line is the height which is perpendicular to the base 120. The height is always perpendicular to the base. The dashed line cuts the base into two equal pieces (this only works for isosceles triangles when you cut at the vertex like this).

So we have two smaller triangles each with a base of 60 and a height of x. Focus on one of the right triangles and use the pythagorean theorem to solve for x.

a^2 + b^2 = c^2

x^2 + (60)^2 = (100)^2

x^2 + 3600 = 10000

x^2 = 10000 - 3600

x^2 = 6400

x = sqrt(6400)

x = 80

Each smaller right triangle has side lengths of 60, 80, 100

Note the ratio 60:80:100 reduces to 3:4:5. A 3-4-5 right triangle is a very common pythagorean primitive.

5 0
3 years ago
Read 2 more answers
Write x2 - 8x + 13 = 0 in the form (x - a)2 = b, where a and b are integers. a.)(x - 4)2 = 3 b.) (x - 3)2 = 2 c.)(x - 2)2 = 1 d.
loris [4]
The answer is <span>a.)(x - 4)2 = 3.

(x - a)</span>² = b can be expressed as:
x² - 2ax + a² = b                                 ⇒ x² - 2ax + a² - b = 0

Our equation is                x² - 8x + 13 = 0.
The general formula is    x² - 2ax + (a² - b) = 0

Thus:
8x = 2ax    and a² - b = 13

Divide both sides of the first equation (8x = 2ax) by x:
8 = 2a           ⇒ a = 8 ÷ 2 = 4

Replace a in the second equation (a² - b = 13):
4² - b = 13     ⇒ b = 4² - 13 = 16 - 13 = 3

Now when we have a and b, let's just replace them in the general equation:
(x - a)² = b
(x - 4)² = 3
4 0
3 years ago
A sample of 140 Vopstra customers have had their annual phone charge recorded for the previous calendar year. The data were used
taurus [48]

Answer:

Correct option: (a)

Step-by-step explanation:

A confidence interval is an interval estimate of the parameter value.

A (1 - <em>α</em>)% confidence interval implies that the confidence interval has a (1 - <em>α</em>)% probability of consisting the true parameter value.

OR

If 100 such confidence intervals are made then (1 - <em>α</em>) of these intervals would consist the true parameter value.

The 92% confidence interval for the mean annual phone charge of all Vopstra customers is:

\$470\pm \$65=(\$405, \$535)

This confidence interval implies that true mean annual phone charge of all Vopstra customers is contained in the interval ($405, $535) with 0.92 probability.

Thus, the correct option is (a).

6 0
3 years ago
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