Answer:
The work done on the suitcase is, W = 600 J
Explanation:
Given,
The average force exerted by Jose on his suitcase, F = 60 N
Jose carried the suitcase to a distance, S = 10 m
The work done on the suitcase is given by the relation
<em>W = F x S</em>
Substituting the given values in the above equation,
W = 60 N x 10 m
= 600 J
Hence, the work done on the suitcase is, W = 600 J
Answer:
16.8 seconds
Explanation:
Given that:
Constant speed of rabbit = 4.2 m/s
Initial Velocity (u) of cat = 0
Acceleration (a) of cat = 0.5 m/s²
Time it takes cat to catch rabbit ;
Using the relation:
Distance moved by rabbit (Dr) :
Dr = speed * time ; Dr = 4.2t
Distance moved by Cat (Dc) :
Dc = ut + 0.5at^2
Dc = 0 + 0.5at^2
Hence, Cat will catch rabbit when Dr = Dc
4.2t = 0.5at^2
4.2t = 0.5(0.5)t^2
4.2t = 0.25t^2
Divide both sides by t
4.2 = 0.25t
t = 4.2 / 0.25
t = 16.8 seconds
Hence, the cat will catch the rabbit after 16.8 seconds
Answer:
16.7 mF
Explanation:
The total capacitance of two capacitors connected in series is given by the formula:

in our problem, we have:
C1 = 45 mF is the capacitance of the first capacitor
C2 = 26 mF is the capacitance of the second capacitor
Substituting into the equation, we find:

I'm pretty sure it's D. negative acceleration
False.
The mass of a softball is approximately 200 g (0.2 kg), while the knees are located approximately at 30 cm (0.3 m) from the ground. It means that the gravitational potential energy of the ball when it is dropped is

This corresponds to the total mechanical energy of the ball at the moment it is dropped, because there is no kinetic energy (the ball starts from rest). Then the ball is dropped, and just before it hits the ground, all this energy is converted into kinetic energy: but energy cannot be created, so its final kinetic energy cannot be greater than 0.6 J.