Answer:
The answer is 12.67 TMU
Explanation:
Recall that,
worker’s eyes travel distance must be = 20 in.
The perpendicular distance from her eyes to the line of travel is =24 in
What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?
Now,
We solve for the given problem.
Eye travel is = 15.2 * T/D
=15.2 * 20 in/24 in
so,
= 12.67 TMU
Therefore, the MTM -1 of normal time that should be allowed for the eye travel element is = 12.67 TMU
Answer:
a. slope=rise/run
rise=0.02
run=-2
determined using the point (3,0.08) and (1,0.1) on the graph
slope=0.02/-2
= -0.01 or -1/100
b.area= area of trapizoid+ rectangle
((0.07+0.11)÷2)×4+1×0.07
0.36+0.07
=0.43$
c. the area represent the total cost after 5 hours
PLEASE MARK BRAINLIEST
Answer:
Scientific theories and laws develop from the acquisition of scientific knowledge.
Explanation:
t
F=ma
Velocity is Distance over time so Vf = 75/15 = 5m/s
Find acceleration V=Vo+at. plugging in the values you know, you get
0.33m/s^2
F=(2100)(0.33)=693N
Answer:
t = 1.659s
Explanation:
We can use the kinematics equations to solve this questions:
v = u + at
where v = Final Velocity, u = initial velocity, a = acceleration, t = time, s = displacement
a) Given information from the question,
u = 
(Convert km/h to m/s first)
a = 
s = 35m
Now we can substitute these values into the 2nd kinematics equation to find v, final velocity.
b) Now we have the final velocity, we can substitute the values into the first kinematics equation to find t , the time taken.
v = u + at
22.761 = 19.444 + 2t
2t = 22.761 - 19.444
t =
t = 1.659s
