Answer:
10.5 mole
Explanation:
Data given:
no. of mole xenon hexafluoride = 10.5 moles
no. of mole cesium fluoride = 11 moles
moles of CsXeF₇ = ?
Reaction Given:
CsF(s) + XeF₆(s) ---------> CsXeF₇(s)
Solution:
First we will look for the reaction
CsF(s) + XeF₆(s) ---------> CsXeF₇(s)
if we look for the mole ratio of CsF to XeF₆
CsF(s) + XeF₆(s) ---------> CsXeF₇(s)
1 mole 1 mole
It means there is 1:1 that is one mole of CsF combine 1 mole XeF₆ to form CsXeF₇. So if we look at the given data cesium fluoride is in excess than XeF₆
Excess amount of CsF = 11.0 mole - 10.5 mole = 0.5 mole
So XeF₆ is limiting reactant and formation of product depends on the amount of XeF₆.
So again look at the reaction on the base of limiting reactant
CsF(s) + XeF₆(s) ---------> CsXeF₇(s)
1 mole 1 mole
it means 1 mole XeF₆ produces 1 mole of CsXeF₇, then how many moles of CsXeF₇ will be produce from 10.5 moles of XeF₆
Apply unity formula
1 mole XeF₆ ≅ 1 mole of CsXeF₇
10.5 mole XeF₆ ≅ X mole of CsXeF₇
Do cross multiplication
mole of CsXeF₇ = 10.5 mole x 1 mole / 1 mole
mole of CsXeF₇ = 10.5 mole
So,
10.5 mole of CsXeF₇ will be produces.
