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Karolina [17]
3 years ago
9

Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 d

egrees Celsius, the Henry's law constant for CO2 in water is 3.1 * 10^-2 mol/L*atm.
? M
Chemistry
1 answer:
OLEGan [10]3 years ago
5 0

Answer : The concentration of CO_2 is, 0.12 M

Explanation :

Using Henry's law :

C_{CO_2}=k_H\times p_{CO_2}

where,

C_{CO_2} = concentration of CO_2 = ?

p_{CO_2} = partial pressure of CO_2 = 4.5 atm

k_H = Henry's law constant  = 3.1\times 10^{-2}mol/L.atm

Now put all the given values in the above formula, we get:

C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)

C_{CO_2}=0.1395M\approx 0.12M

Thus, the concentration of CO_2 is, 0.12 M

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Write the net ionic equ.
Artyom0805 [142]

Answer:

a) AgNO3 + KI → AgI + KNO3

b) Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O

c) 2Na3PO4  + 3Ni(NO3)2  → Ni3(PO4)2 + 6NaNO3

d) 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

Explanation:

a) AgNO3 + KI → Ag+ + NO3- + K+ + I-

Ag+ + NO3- + K+ + I-  → AgI + KNO3

AgNO3 + KI → AgI + KNO3

b) Ba(OH)2 + 2HNO3 → Ba^2+ + 2OH- + 2H+ + 2NO3-

Ba^2+ + 2OH- + 2H+ + 2NO3- → Ba(NO3)2 + 2H2O

Ba(OH)2 + 2HNO3 → Ba(NO3)2 + 2H2O

c) 2Na3PO4  + 3Ni(NO3)2 → 6Na+ + 2PO4^3- + 3Ni^2+ + 6NO3-

6Na+ + 2PO4^3- + 3Ni^2+ + 6NO3- →  Ni3(PO4)2 + 6NaNO3

2Na3PO4  + 3Ni(NO3)2  → Ni3(PO4)2 + 6NaNO3

d) 2Al(OH)3 + 3H2SO4 → 2Al^3+ + 6OH- + 6H+ + 3SO4^2-

2Al^3+ + 3OH- + 3H+ + 3SO4^2- → Al2(SO4)3 + 6H2O

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

7 0
3 years ago
If 0.0714 moles of N2 gas occupies 1.25 L space, how many moles of N2 have a volume of 25.0 L? Assume temperature and pressure s
vfiekz [6]

Answer:

1.428 moles

Explanation:

If 0.0714 moles of N2 gas occupies 1.25 L space,

how many moles of N2 have a volume of 25.0 L?

Assume temperature and pressure stayed constant.

we experience it 0.0714 moles: 1.25L space

x moles : 25L of space

to get the x moles, cross multiply

(0.0714 x 25)/1.25

1.785/1.25 = 1.428 moles

8 0
3 years ago
Which of the following is not a chemistry topic?
Tju [1.3M]
I’m pretty sure it’s D
6 0
3 years ago
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Hat volume of a 0.540 M NaOH solution contains 12.5 g NaOH
amid [387]

Answer:

At 0.58 L of 0.540 M NaOH solution contain 12.5 g NaOH.

Explanation:

Given data:

At volume = ?

Mass of NaOH = 12.5 g

Molarity of solution = 0.540 M

Solution:

First of all we will calculate the number of moles of sodium hydroxide.

Number of moles = mass/molar mass

Number of moles = 12.5 g / 40 g/mol

Number of moles = 0.3125 mol

Volume of NaOH:

Molarity = number of moles / volume in L

Now we will put the values.

0.540 M = 0.3125 mol / volume in L

volume in L = 0.3125 mol / 0.540 mol/L

volume in L = 0.58 L

5 0
3 years ago
How many grams of CO2 are in 10 mol of the compound?
IrinaK [193]
The answer is 60 grams.
3 0
3 years ago
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