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Karolina [17]
3 years ago
9

Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 d

egrees Celsius, the Henry's law constant for CO2 in water is 3.1 * 10^-2 mol/L*atm.
? M
Chemistry
1 answer:
OLEGan [10]3 years ago
5 0

Answer : The concentration of CO_2 is, 0.12 M

Explanation :

Using Henry's law :

C_{CO_2}=k_H\times p_{CO_2}

where,

C_{CO_2} = concentration of CO_2 = ?

p_{CO_2} = partial pressure of CO_2 = 4.5 atm

k_H = Henry's law constant  = 3.1\times 10^{-2}mol/L.atm

Now put all the given values in the above formula, we get:

C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)

C_{CO_2}=0.1395M\approx 0.12M

Thus, the concentration of CO_2 is, 0.12 M

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15 grams of sodium reacts with a certain amount of chlorine to yield 37 grams of sodium chloride, as shown below.
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3 years ago
How many moles of agcl are contained in 244 ml of 0.135 magcl solution? the density of the solution is 1.22 g/ml?
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