Question

Calculate the concentration of CO2 in water at 25 degrees Celsius when the pressure of CO2 over the solution is 4.5 atm. At 25 degrees Celsius, the Henry's law constant for CO2 in water is 3.1 * 10^-2 mol/L*atm.
? M

Answer 1

Answer : The concentration of $CO_2$ is, 0.12 M

Explanation :

Using Henry's law :

$C_{CO_2}=k_H\times p_{CO_2}$

where,

$C_{CO_2}$ = concentration of $CO_2$ = ?

$p_{CO_2}$ = partial pressure of $CO_2$ = 4.5 atm

$k_H$ = Henry's law constant  = $3.1\times 10^{-2}mol/L.atm$

Now put all the given values in the above formula, we get:

$C_{CO_2}=3.1\times 10^{-2}mol/L.atm\times (4.5atm)$

$C_{CO_2}=0.1395M\approx 0.12M$

Thus, the concentration of $CO_2$ is, 0.12 M