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iren2701 [21]
4 years ago
8

How many grams of NaCl are required to make 150.0mL of a 5.000 m solution

Chemistry
1 answer:
Yanka [14]4 years ago
6 0

The  number of  grams of NaCl  required  to make 150.0 ml of a 5.000m solution  is  43.875  grams


<u><em>calculation</em></u>

Step 1:  calculate  moles of NaCl

moles=  molarity x  volume in liters

volume in liters =  150.0  ml/1000= 0.15  l

moles is=  5.000mol/l  x0.15  l  =0.75  moles


Step2 :  find  mass

mass=  moles  x molar  mass

molar mass  of NaCl= 23 +35.5 = 58.5  g/mol

mass= 0.75  moles x58.5 g/mol = 43.875 grams

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Calculate the percent composition of chlorine in methyl trichloride, CHCl3.
vovikov84 [41]

Answer:

Chlorine --> 89%

Explanation:

Step 1) Add each element's amu up to get the total mass of the compound.

12.011+1.008+3(35.453) = 119.378.

Step 2) Divide the total mass of chlorine by the total mass of the compound.

3(35.453) = 106.359

106.359/119.378 = 0.8909430548.

Step 3) Now multiply by 100 to get the percentage.

0.8909430548*100 = 89.09430548%

Step 4) Estimate and submit your answer

89.09430548% estimates to 89%

5 0
3 years ago
Help please I need it bad
natta225 [31]
= 9.1 × 10^6
(scientific notation)

= 9.1e6
(scientific e notation)

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(million; prefix mega- (M))

= 9100000
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5 0
3 years ago
How many moles is 5.05 x 10^24 atoms of magnesium?
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Ammonia and hydrogen fluoride both have unusually high boiling points due to
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A + B = Products
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