Since we are basing the rate with respect to O3, therefore
the rate would simply be the concentration divided by the total reaction time.
That is:
rate of reaction = 0.05 M / 16 seconds
rate of reaction = 3.125 x 10^-3 M / second
or
<span>rate of reaction = 0.003125 M / second</span>
Everything but "<span>The tire is flat because of a decrease in temperature" is an observation.</span>
M = m/L
moles of CaO = 2.75g / molar mass
2.75g/ 56.08g = 0.049moles CaO
155mL / 1000 = 0.155 L
M= 0.049moles/0.155L
M=0.316
