Answer:
A) attached below
B) 743 KJ
C) 1.8983 KJ/K
Explanation:
A) Diagram of system schematic and set up states
attached below
<u>B) Calculate the amount of work received from the paddle wheel </u>
assuming ideal gas situation
v1 = v2 ( for a constant volume process )
work generated by paddle wheel = system internal energy
dw = mCv dT . where ; Cv = 0.743 KJ/kgk
= 5 * 0.743 * ( 500 - 300 )
= 3.715 * 200 = 743 KJ
<u>C) calculate the amount of entropy generated ( KJ/K )</u>
S2 - S1 = 1.8983 KJ/K
attached below is the detailed solution
Answer:
A. 72.34mol/min
B. 76.0%
Explanation:
A.
We start by converting to molar flow rate. Using density and molecular weight of hexane
= 1.59L/min x 0.659g/cm³ x 1000cm³/L x 1/86.17
= 988.5/86.17
= 11.47mol/min
n1 = n2+n3
n1 = n2 + 11.47mol/min
We have a balance on hexane
n1y1C6H14 = n2y2C6H14 + n3y3C6H14
n1(0.18) = n2(0.05) + 11.47(1.00)
To get n2
(n2+11.47mol/min)0.18 = n2(0.05) + 11.47mol/min(1.00)
0.18n2 + 2.0646 = 0.05n2 + 11.47mol/min
0.18n2-0.05n2 = 11.47-2.0646
= 0.13n2 = 9.4054
n2 = 9.4054/0.13
n2 = 72.34 mol/min
This value is the flow rate of gas that is leaving the system.
B.
n1 = n2 + 11.47mol/min
72.34mol/min + 11.47mol/min
= 83.81 mol/min
Amount of hexane entering condenser
0.18(83.81)
= 15.1 mol/min
Then the percentage condensed =
11.47/15.1
= 7.59
~7.6
7.6x100
= 76.0%
Therefore the answers are a.) 72.34mol/min b.) 76.0%
Please refer to the attachment .
Answer:
The line voltage of the three phase network is 346.41 V
Explanation:
Star Connected Load
Resistance, R₁ = R₂ = R₃ = 18 Ω
For a star connected load, the line current = the phase current, that is we have

Whereby the the voltage across each resistance =
is given by the relation;
=
× R
Hence;
=
=
× R = 25 × 8 = 200 V
Therefore we have;
The line voltage,
= √3 ×
= √3 × 200 = 346.41 V.
Hence, the line voltage of the three phase network = 346.41 V.
Answer:
Torque: 500
Power: 1700
Explanation:
Since the force is 150 lbs and if the shaft is rotating at 350 rpms, then you will need 1700 for the power in order to keep it running.