Answer:
2.455 W
Explanation:
The power dissipated in each branch is ...
P = V^2/R
So, the branch powers are ...
branch 1: 18^2/220 ≈ 1.473 W
branch 2: 18^2/330 ≈ 0.982 W
Total power is ...
1.473 W + 0.982 W = 2.455 W
Answer:because it faster
Explanation: and when building a device or vehicle that requires large
Answer:
The right solution is "28.45%".
Explanation:
The given values are:



and,





At 45,
⇒ 

At
,

or,

then,
⇒ 

hence,
The isentropic efficiency of turbine will be:
⇒ 

(%)
The thermal efficiency of cycle will be:
⇒ 

(%)
Answer:
938.7 milliseconds
Explanation:
Since the transmission rate is in bits, we will need to convert the packet size to Bits.
1 bytes = 8 bits
1 MiB = 2^20 bytes = 8 × 2^20 bits
5 MiB = 5 × 8 × 2^20 bits.
The formula for queueing delay of <em>n-th</em> packet is : (n - 1) × L/R
where L : packet size = 5 × 8 × 2^20 bits, n: packet number = 48 and R : transmission rate = 2.1 Gbps = 2.1 × 10^9 bits per second.
Therefore queueing delay for 48th packet = ( (48-1) ×5 × 8 × 2^20)/2.1 × 10^9
queueing delay for 48th packet = (47 ×40× 2^20)/2.1 × 10^9
queueing delay for 48th packet = 0.938725181 seconds
queueing delay for 48th packet = 938.725181 milliseconds = 938.7 milliseconds
Explanation:
inside diameter of the hose