Answer:
Could you post the rest of it pllease
Step-by-step explanation:
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Step-by-step explanation:
the second one as the -2x-3 is only on the second one
We want to find the value that makes
To find it we must look at the standard normal table, using the complementary cumulative table we find that
Then, using the z-score we can find the minimum score needed, remember that
Where
σ = standard deviation
μ = mean
And in our example, x = minimum score needed, therefore
Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.
X-6y=6 slope: 1/6 y-intercept (0,1)
X= 0,6 y= -1, 0
X+3y+12=0 slope: 1/3
Y-intercept (0,4) x= -12, 0 Y= 0,4
8a-9b= 9/8 slope (0 ,7/8) x= -1,1 Y= -1/4,2
3a+b=7 1/3 (0,7/3) x= 4,7 Y=1,0
