Answer:
#_photon = 5 10²⁰ photons / s
Explanation:
For this exercise let's calculate the energy of a single quantum of energy, use Planck's law
E = h f
c= λ f
E = h c / λ
λ= 1000 nm (1 m / 109 nm) = 1000 10⁻⁹ m
Let's calculate
E₀ = 6.6310⁻³⁴ 3 10⁸/1000 10⁻⁹
E₀ = 19.89 10⁻²⁰ J
This is the energy emitted by a photon let's use a proportions rule to find the number emitted in P = 100 w
#_photon = P / E₀
#_photon = 100 / 19.89 10⁻²⁰
#_photon = 5 10²⁰ photons / s
Answer:
1) the unit of power is A.Watt
2)100J=50W
100=50s
divide both sides by 50s
S=2s(A)
Answer:
Explanation: Decreasing in velocity
Answer: 1339.5 joules
Explanation:
Gravitational potential energy, GPE is the energy possessed by the jumper as he moves against gravity.
Thus, GPE = Mass m x Acceleration due to gravity g x Height h
Since Mass = 67kg
g = 9.8m/s^2
h = 2.04 metres
Thus, GPE = 67kg x 9.8m/s^2 x 2.04m
GPE = 1339.5 joules
Thus, the gravitational potential energy at the highest point is 1339.5 joules
