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Jobisdone [24]
3 years ago
14

Scientists think that a few hundred million years or so after the Big Bang, space cooled off enough for matter to form. This mat

ter spread out around the universe with no structure. But each little bit of matter exerted the force of _____ on each other little bit.
Physics
2 answers:
Eva8 [605]3 years ago
6 0
This matter spread out around theuniverse with no structure. But each little bit of matter exerted the force of gravity on each other little bit. Gravity is the only type of force connected with <span>the Big Bang as it is a basic force that was to create our world in th way we can see and discover it today.</span>
Lera25 [3.4K]3 years ago
4 0

Answer: Gravity

Explanation:  The force that is generated by matter is the gravitational force, is the force that attracts the bits of matter to each other, and is described by the equation:

F = G*(m₁*m₂)/r^2

Where G is the gravitational constant, m₁ and m₂ are the masses of the bits of matter, and r is the distance between them.

The complete paragraph is:

Scientists think that a few hundred million years or so after the Big Bang, space cooled off enough for matter to form. This matter spread out around the universe with no structure. But each little bit of matter exerted the force of gravity on each other a little bit.

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daser333 [38]

Answer:

Welcome ShalomMHNCB Phx

Explanation:

the answer is because I just had this question and I got it wrong so te answer is 0.43

4 0
3 years ago
Pakistan and bangladesh are two countries on the subcontinent
gregori [183]

Answer:

Indian subcontinent  

Explanation:

The Indian subcontinent is a southern region and peninsula of Asia which include seven countries. The seven countries in Indian subcontinent are Pakistan, Bangladesh, India, Bhutan, Maldives, Sri Lanka and Nepal. According to Wikipedia, about 55 million years ago, the Indian subcontinent has land mass that rifted from Gondwana and merged with the Eurasian plate.

5 0
3 years ago
At some of the greatest distances probed by telescopes, where many ordinary galaxies are too dim to be seen, we find the brillia
Simora [160]

Answer:

The brilliant galaxy centers are known as quasars. According to the astronomers quasars exists at the center o galaxies and in the center of galaxies there exists the black holes. Quasars are known as the brightest objects of the universe and they appear like a star in the telescopes.

Explanation:

5 0
3 years ago
A sling is used to give a stone an initial velocity of 20 at an angle of 30 above the horizontal. The stone travels through the
Luba_88 [7]

Answer:

Option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Explanation:

Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile = 20 m/s

θ = angle above the horizontal at which the projectile was launched = 30°

g = acceleration due to gravity = 9.8 m/s²

R = (30² sin 60°) ÷ 9.8

R = 78.53 m

So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Hope this Helps!!!

7 0
4 years ago
An electric kettle is rated at 2 kW when connected to a 230 V electrical supply
Oliga [24]

Explanation:

a) P = IV

2000 W = I (230 V)

I = 8.7 A

b) The fuse must be rated for a higher current than the kettle, so use the 13A fuse.

c) Double insulation means there are two layers of insulation, insuring that the wires cannot touch the outer casing of the kettle and protecting the user from electrical shock.

d) V = IR

230 V = (8.7 A) R

R = 26.5 Ω

6 0
3 years ago
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