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Brums [2.3K]
3 years ago
15

In a mixture of He, Ne, and Kr the total pressure is 125 kPa. The partial

Chemistry
1 answer:
tatiyna3 years ago
7 0

Answer:

Partial pressure of He = 73 kPa

Explanation:

Given:

Total pressure = 125 kPa

Partial  pressure of Ne = 31 kPa

Partial pressure of Kr = 21 kPa

Find:

Partial pressure of He

Computation:

Total pressure = Partial  pressure of Ne + Partial  pressure of Kr + Partial  pressure of He

125 kPa = 31 kPa + 21 kPa + Partial pressure of He

Partial pressure of He = 73 kPa

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List the number of protons, neutrons, and electrons in....( there is a pic)
notsponge [240]
There are 6 protons, 7 neutrons, and 6 electrons since the atomic mass is rounded to 13.
3 0
3 years ago
In order for an atom to be neutral (i.e. have no charge), it must have the same number of ______ as it has protons. a. neutrons
Marina CMI [18]

Answer : The correct option is, (b) There is a same number of electrons.

Explanation :

For the neutral atom, the number of protons and electrons are equal. But, they are unequal when the atoms present in the form of ions or the atom has some charges.

When an unequal number of electrons and protons then it leads to the formation of ionic species.

Ion : An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.

When an atom gains electrons, it will form a negative ion known as anion.

For example : The neutral atom Mg has equal number of protons and electrons i.e 12 but Mg^{2+} ion has unequal number of protons and electrons that means it has 12 number of protons and 10 number of electrons.

Hence, the correct option is, (B) electrons

5 0
4 years ago
Consider the following Reaction.
jeyben [28]

Hey there!:

Molar mass of Mg(OH)2 = 58.33 g/mol


number of moles Mg(OH)2 :

moles of Mg(OH)2 = 30.6 / 58.33 =>  0.5246 moles

Molar mass of H3PO4 =  97.99 g/mol

number of moles H3PO4:

moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles

Balanced chemical equation is:


3 Mg(OH)2 + 2 H3PO4 --->  Mg3(PO4)2 + 6 H2O


3 mol of Mg(OH)2 reacts with 2 mol of H3PO4  ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !

Now , we will use Mg(OH)2 in further calculation  .

Molar mass of Mg3(PO4)2 = 262.87 g/mol

According to balanced equation  :

mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2


= (1/3)*0.5246


= 0.1749 moles of Mg3(PO4)2

use :

mass of Mg3(PO4)2 = number of mol * molar mass


= 0.1749 *  262.87

= 46 g of Mg3(PO4)2

Therefore:

% yield = actual mass * 100 / theoretical mass

% = 34.7 * 100 / 46

% = 3470 / 46

= 75.5%


Hope that helps!




3 0
3 years ago
C6h5-c=o-ch3 + br2/oh
Natali [406]

Explanation:

here's the molecule you were looking for

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3 years ago
Which element would you expect to behave the most like carbon (c)? apex?
chubhunter [2.5K]
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3 years ago
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