Question

There are seven black marbles and nine white marbles in a bag what is the aprroximate probability of drawing two black marbles and then a white marble without replacement

Answer 1

Well, first in total there are 16 marbles. So the change of getting a black is 7/16. Now we have 15 marbles. The chance is 6/15. Now we have 14 marbles. The chance is 9/14. When you multiply 7/16 x 6/15 x 9/14 = 9/80
Hope this works

Answer 2

There are a total of 16 marbles in the bag. Black marbles compound 7/16 or 43.75% of the bag. White marbles compound 9/16 or 56.25% of the bag.

There is a probability of 43.75% to pick a black marble in the bag with 16 marbles.
If you do , there will be 6 black marbles and 9 white marbles left in the bag. The probability to pick anpther black marble is 6/15 or 40%.


If you do pick another black marble , there will be 5 black marbles and 9 white marbles left in the bag , which means the probability of you getting a white marble next is 9/14 or 64.28%.

Now we just have to multiply the probability of you picking the marbles in the right order :

0.4375 × 0.4 × 0.6428 = 0.11249

Which is approximately 11.25%

There is a probability of 11.25% of you getting two black marbles and one white marble in a bag with 7 black marbles and nine white marbles .

I hope you understood my brief explanation. And please consider marking this awnser as Branliest if you think it deserves it. Thank you :)