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3 years ago

Will give brainliest please help!!

Chemistry

1 answer:

amm18123 years ago

3 0

Answer:

I think it's B so maybe

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Ice will ________ in water. A. float B. sink C. stay the same

Marizza181 [45]

Answer:

It floats.

Explanation:

Ice would float because it is about 9% less dense than water

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3 years ago

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Why electrons present around the nucleus of an atom do not fall into the nucleus

andriy [413]

Answer:

Due to electrostatic force

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3 years ago

Describe un modelo matemático para representar lo que sucede en cada una de las reacciones químicas (incluye toda la simbología

GuDViN [60]

Responder:

2H2 + O2 → 2H2O

CaO + H2O → Ca (OH) 2

Fe + S → FeS

H2SO3 → SO2 + H2O

CaCO3 → CaO + CO2

Explicación:

2H2 + O2 → 2H2O

2 moléculas de hidrógeno gaseoso reaccionan con oxigente para producir 2 moléculas de agua

CaO + H2O → Ca (OH) 2

El óxido de calcio reacciona con el agua para producir hidróxido de calcio.

Fe + S → FeS

El hierro reacciona con el azufre para producir sulfuro de hierro.

H2SO3 → SO2 + H2O

Por descomposición, el ácido sulfuroso se descompone para producir dióxido de azufre y agua.

CaCO3 → CaO + CO2

El carbonato de calcio se descompone para producir óxido de calcio y dióxido de carbono.

8 0

3 years ago

What is 44.25 l to ml

Oliga [24]

44250

hope this helps

6 0

3 years ago

a compound has 15.39 g of gold for every 2.77 g of chlorine. simplified there is _____ g of gold for every 1 g of chlorine

iren [92.7K]

Answer:

There is 5.56 g of gold for every 1 g of chlorine

Explanation:

The ratio is the relationship between two numbers, defined as the ratio of one number to the other. So, the ratio between two numbers a and b is the fraction $\frac{a}{b}$

You know that a compound has 15.39 g of gold for every 2.77 g of chlorine. This can be expressed by the ratio:

$\frac{15.39 g of gold}{2.77 g of chlorine}$

The proportion is the equal relationship that exists between two reasons and is represented by: $\frac{a}{b}=\frac{c}{d}$

This reads a is a b as c is a d.

To calculate the amount of gold per 1 g of chlorine, the following proportion is expressed:

$\frac{15.39 g of gold}{2.77 g of chlorine}=\frac{mass of gold}{1 g of chlorine}$

Solving for the mass of gold gives:

$mass of gold=1 g of chlorine*\frac{15.39 g of gold}{2.77 g of chlorine}$

mass of gold= 5.56 grams

So, there is 5.56 g of gold for every 1 g of chlorine

5 0

3 years ago