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3 years ago

Will give brainliest please help!!

Chemistry

1 answer:

amm18123 years ago

3 0

Answer:

I think it's B so maybe

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List the 3 particles that make up an atom.

laila [671]

The 3 particles are protons, neutrons, and electrons?

4 0

3 years ago

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In the decomposition of water, how many grams of hydrogen gas and oxygen gas are produced from 23.44 g of water?

djyliett [7]

Answer:

2.60 g of H₂ and 20.8 g of O₂ are produced in the decomposition of 23.44 g of water

Explanation:

Water decomposition is:

2H₂O → 2H₂ + O₂

We convert the mass of water, to moles:

23.44 g . 1 mol/18 g = 1.30 moles

Ratio is 2:2 with hydrogen and 2:1 with oxygen. Let's make rules of three:

2 moles of water can produce 2 moles of hydrogen gas and oxygen gas

Then, 1.30 moles will produce:

(1.30 . 2) /2 = 1.30 moles of H₂

(1.30 . 1) /2 = 0.65 moles of O₂

We convert the moles to mass

1.30 moles of H₂ . 2g / 1mol = 2.60 g of H₂

0.65 moles of O₂ . 32 g / 1 mol = 20.8 g of O₂

6 0

3 years ago

In average households, what uses the most water each day?

Tanya [424]

Answer:

I think a toilet because it is use a lot once you think about it

8 0

3 years ago

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Hello

nordsb [41]

Answer:

The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.

Explanation:

Let the mass of silver ornament be x.

Mass of gold polished on an ornament = 1% of x= 0.1 x

Moles of silver = $\frac{x}{108 g/mol}$

Number of atoms = $Moles\times N_A$

Where : $N_A$ = Avogadro number

Moles of gold = $\frac{0.1x}{197 g/mol}$

Silver atoms = $\frac{x}{108 g/mol}\times N_A$

Gold atoms = $\frac{0.1x}{197 g/mol}\times N_A$

The ratio of the number of atoms of gold and silver in the ornament:

$=\frac{\frac{0.1x}{197 g/mol}\times N_A}{\frac{x}{108 g/mol}\times N_A}$

= 197 : 1080

3 0

3 years ago

Density of a piece of wood that has a measurement of 24 cm3 and 768 g

Brut [27]

Answer:

<h3>The answer is 32 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 768 g

volume = 24 cm³

We have

$density = \frac{768}{24} \\$

We have the final answer as

Hope this helps you

4 0

4 years ago

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