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Answer:
The height reached by the material on Earth is 91 km.
Explanation:
Given that,
Mass 
Radius = 1821 km
Height 
Suppose we need to find that how high would this material go on earth if it were ejected with the same speed as on Io?
We need to calculate the acceleration due to gravity on Io
Using formula of gravity

Put the value into the formula


Let v be the speed at which the material is ejected.
We need to calculate the height
Using the formula of height

Using ratio of height of earth and height of Io


Put the value into the formula





Hence, The height reached by the material on Earth is 91 km.
Answer:
Explanation:
r=A(1 m/s)t^i+A((1 m/s3)t3−6(1 m/s2)t2)^j,
dr / dt = A i + (3 A t² - 6 x 2 t ) j
At t = 2
dr / dt = A i + (12A - 24 A ) j = A i - 12 A j .
Since slope is negative so velocity is downwards , hence it is descending
b ) velocity = dr / dr = . A i + (3 A t² - 6 x 2 t ) j
Vx = A
Vy = 3A t² - 12 t
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The concept required to perform this exercise is given by the coulomb law.
The force expressed according to this law is given by

Where,

q = charges of the objects
r= distance/radius
Our values are previously given, so

Replacing,



The force acting on the block are given by,




Therefore the box is accelerated upward.