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Kay [80]
3 years ago
12

A person drives 70 km/h in 1 hour to the east, then 80 km/h for another hour to the east. What

Physics
1 answer:
andre [41]3 years ago
6 0

Answer: The average velocity is 150 km/h

Explanation: 70+80=150

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A rifle that shoots bullets at 477 m/s is to be aimed at a target 45.5 m away. If the center of the target is level with the rif
Free_Kalibri [48]

Answer:

The rifle barrel must be pointed at a height of 4.45cm above the target so that the bullet hits dead center.

Explanation:

First, we need to sketch the situation so we can have a better idea of what the problem looks like (Refer to uploaded picture).

So as you may see in the drawing, when pointing the rifle to the target, we can see it as a triangle, but in reality, the bullet will have a parabolic trajectory. Both points of view will help us determine what the height must be. In order to find it, we need to first determine at what angle the bullet should be shot. In order to do so we can use the range formula, which looks like this:

R=\frac{v^{2}sin(2\theta)}{g}

Where R is the range of the bullet (this is how far it goes before it has the

same height it was shot from), v is the original speed of the bullet, θ is the angle at which the bullet is shot and g is the acceleration of gravity.

We can solve this equation for theta, so we get:

gR=v^{2}sin(2\theta)

\frac{gR}{v^{2}}=sin(2\theta)

sin^{-1}(\frac{gR}{v^{2}})=2\theta

\theta=\frac{sin^{-1}(\frac{gR}{v^{2}})}{2}

so now we can substitute the given data:

\theta=\frac{sin^{-1}(\frac{(9.8m/s^{2})(45.5m)}{(477m/s)^{2}})}{2}

so we get:

θ=0.05614°

once we get the angle, we can look at the triangle diagram. From the drawing we can see that we can use the tan function to find the height:

tan \theta = \frac{h}{45.5m}

so we can solve this for h, so we get:

h=45.5m*tan(0.05614^{o})

which yields:

h=0.0445m

or

h=4.45cm

5 0
3 years ago
The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent ho
faltersainse [42]

Answer:

Explanation:

Let mass of cylinder be M

Moment of inertia of cylinder

= 1/2 M R² r is radius of cylinder

If radius of equivalent  hoop be k

Mk² = 1/2 x MR²

k = R / √2

1.2 / 1.414

Radius of gyration = 0.848 m

b )

moment of inertia of spherical shell

= 2 / 3 M R²

Moment of inertia of equivalent hoop

Mk²

So

Mk² = 2 / 3 M R²

k = √2/3 x R

= .816 X 1.2

Radius of gyration = .98 m

c )

Moment of inertia of solid sphere

= 2/5 M R²

Moment of inertia of equivalent hoop

= Mk²

Mk² = 2/5 M R²

k √ 2/5 R

Radius of gyration = .63 R

6 0
3 years ago
To save money on buying mercury you build a BAROMETER using water as the fluid inside the column. Approximately, how tall is you
kirill115 [55]

To solve this problem we need to use the concepts related to fluid density. Since we need to know a height point of two different liquids, their pressures must be equal, so

P_1 = P_2

\rho_1 gh_1 = \rho_2gh_2

Where,

\rho =Density

g = Gravitational acceleration

h = Height

Our values are given as,

\rho_1 = 1.36*10^4kg/m^3

\rho_2 = 1*10^3kg/m^3

h = 76.02cm \rightarrow Standard mercury pressure at 1atm, the barometer height is 760.2mm.

Replacing we have,

1.36*10^4 *76.02= 10^3*h_2

h_2 = 1033.87cm

Therefore the tall of the barometer would be 1033.87 (Inconvenient compared with the Mercury Barometer)

8 0
3 years ago
In Fig. P24.59, each capacitance C1 is 6.9 mF, and each capacitance C2 is 4.6 mF. (a) Compute the equivalent capacitance of the
mrs_skeptik [129]

(a) Equivalent capacitance of network between points a and b is 2.3μF.

(b) Charge on each of the three capacitors nearest a and b is 920 μC.

A) Let's consider the right side that is farthest from the point 'a'.

Three C1 are connected in series

C= 1/C1 + 1/C1 +1/C1 = C1/3

C = 6.9/3 = 2.3μF

Now this C is connected in parallel with C2

So, C= 2.3 + 4.6 = 6.9μF

Again we get three capacitors of 6.9μF each, connected in series.

C = C1/3 = 2.3μF

It again combines with 4.6μF in parallel

C = 4.6 + 2.3 =6.9μF

Now, this final reduction is the same as that of the first.

In the end, we have 3 capacitors of 6.9μF each connected in series.

Equivalent Capacitance C(eq) = C1/3 = 6.9/3 = 2.3μF

         = 2.3 × 10^{-6} F

B) C(eq) = 2.3 × 10^{-6} F

Vab = 400 V (Given)

Charge on each of the three capacitors nearest a and b (Q) =?

Q = C(eq) × Vab

   = 2.3 × 10^{-6} × 400 = 9.2 × 10^{-4} C = 920μC

Hence, the equivalent capacitance of the network between points a and b is 2.3μF.

And Charge on each of the three capacitors nearest a and b is 920 μC.

Learn more about Capacitance here brainly.com/question/13578522

#SPJ1

8 0
2 years ago
What is the Milky Way?
Kruka [31]

Answer:

A spiral galaxy in which Earth is located

Explanation:

Because spiral galaxies are characterized by a distinct flattened spiral disk with a bright center called the nucleus making it lookl ike a hurricane symbol on weather hurricane trackers. Our very own Milky Way is a spiral galaxy and Eaerth is located rigth in their.

5 0
3 years ago
Read 2 more answers
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