During a total lunar eclipse, the Moon located in the umbra.
The answer is letter A. For a total lunar eclipse to occur, the Sun, Earth and
Moon must be aligned in a straight line. The Earth’s umbra complete covers the
Moon. The earth’s umbra is about 870,000 miles wide.
The roller coaster is moving in a circular path, so the force that must be computed is the centripetal force. The centripetal force is the force acting on an object undergoing circular motion and is directed towards the center of the circular path. This is computed using:
F = mv²/r
F = (500 * 18²) / 12
F = 13,500 N
Now, at the bottom of the track, the track is also supporting the weight of the car and its passengers, which is:
W = mg
W = 500 * 9.81
W = 4,905 N
The total reactive force exerted by the track to counter the centripetal force and the weight of the car is:
F = 13,500 + 4,905
F = 18,405 Newtons
Answer:
Fission is the process by which large nuclei (like Uranium) split apart releasing energy. Fusion is the joining of nuclei to make larger nuclei, with the release of energy. A ball of contracting interstellar gas becomes a star like the Sun when fusion reactions start in its center. Then, we say "a star is born."
Answer:
3.6 x 10^8 V
Explanation:
Q = 4 m C = 4 x 10^-3 C
r = 5 cm = 0.05 m
The formula for the potential at the surface is
Vs = K Q / r = (9 x 10^9 x 4 x 10^-3) / 0.05 = 7.2 x 10^8 V
The formula for the potential at the centre is
Vc = 3/2 Vs
Vc = 1.5 x 7.2 x 10^8 V = 10.8 x 10^8 V
The difference in potential is
V = Vc - Vs = 10.8 x 10^8 - 7.2 x 10^8 = 3.6 x 10^8 V
