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Evgesh-ka [11]
3 years ago
12

PLEASE ANSWER DOWN BELOW

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

Answer:

what do you need help with which part

Step-by-step explanation:

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7 pizzas ordered and ate 5 6/8. what's left?
Nookie1986 [14]
2 2/8 or 2 1/4 if thats what you are asking for
7 0
3 years ago
PPPLLLLEEEAASSSEEEE HHHEEEELLLLPPPPP!!!!!!!
Yuliya22 [10]

Answer:

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Step-by-step explanation:

Because the center of dilation is at (0, 0), or the origin, we can just multiply the x and y values of each point by the scale factor of 13.

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Read more on Brainly.com - brainly.com/question/11445104#readmore

4 0
4 years ago
Is (0.3) the solution to the equation y=x+3
Goryan [66]

Answer:-3

Step-by-step explanation:Could it be -3 if your learning about intercepts I need more information to help you further

7 0
3 years ago
Read 2 more answers
Which expression is equivalent to 15a^8b^4/5a^4b?<br> 3a^2b^4<br> 3a^4b^3<br> 10a^4b^3<br> 10a^4b^4
EleoNora [17]

Answer:

3 a^12 b^5

Step-by-step explanation:

Simplify the following:

(15 a^8 b^4 a^4 b)/5

15/5 = (5×3)/5 = 3:

3 a^8 b^4 a^4 b

3 a^8 b^4 a^4 b = 3 a^(8 + 4) b^(4 + 1):

3 a^(8 + 4) b^(4 + 1)

4 + 1 = 5:

3 a^(8 + 4) b^5

8 + 4 = 12:

Answer: 3 a^12 b^5

5 0
3 years ago
Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
n^{2}  \neq 2
n \neq +or- \sqrt{2}
5 0
4 years ago
Read 2 more answers
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