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il63 [147K]
3 years ago
15

You toss a ball straight upward, in a positive direction. The ball falls freely under the influence of gravity. At the highest p

oint in the ball's motion.
A.) its velocity is zero and its acceleration is positive (upward).

B.) its velocity is zero and its acceleration is negative (downward).

C.) its velocity is positive (upward) and its acceleration is zero.

D.) its velocity is zero and its acceleration is zero.
Physics
1 answer:
Sindrei [870]3 years ago
4 0

Answer:

B.) its velocity is zero and its acceleration is negative (downward).

Explanation:

When the ball is thrown upwards in the air, the ball starts with its velocity being high and positive upwards against the force of gravity. Due to force of gravity pulling the object to the center of the earth, its velocity decreases as it reaches the maximum height where the velocity is instantaneously zero. At this maximum height its acceleration is -9.81 m/s².

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Substance a is a solid ionic compound substance b solid covalent compound what would happen if you put them both in the same con
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4 years ago
A proton and an electron are fixed in space with a separation of 859 nm. Calculate the electric potential at the midpoint betwee
makkiz [27]

Answer:

The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

Explanation:

Electric potential is given as;

V = E*r

where;

E is the electric field strength, = kq/r²

V = ( kq/r²)*r

V = kq/r

k is coulomb's constant = 8.99 X 10⁹ Nm²/C²

q is the charge of the particles = 1.6 X 10⁻¹⁹ C

r is the distance between the particles = 859 nm

At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm

V = (8.99 X 10⁹  * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)

V = 3.349 X 10⁻³ Volts

Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts

3 0
3 years ago
Two point charges exert a 7.35 N force on each other. What will the force become if the distance between them is increased by a
I am Lyosha [343]

Answer :

New force becomes, F' = 1.83 N

Explanation:

Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}

q_1\ and\ q_2 are charges

r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r

New force is given by :

F'=\dfrac{kq^2}{r'^2}

F'=\dfrac{kq^2}{(2r)^2}

F'=\dfrac{1}{4}\dfrac{kq^2}{r^2}

F'=\dfrac{1}{4}\times 7.35

F' = 1.83 N

So, the new force between charges will be 1.83 N. Therefore, this is the required solution.          

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3 years ago
A tuning fork is vibrating the air around it. What best describes the waves produced by the tuning fork?
never [62]

The answer is B on the quiz

9 0
3 years ago
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