THE DOPPLER EFFECT. Anyways, it would have a higher whistle as it approaches you, when it gets to you it only gets quieter because it leaves after. Think of a motorcycle going by, its loud coming to you then as it passes it gets quieter.
Answer:
The period of oscillation is 1.33 sec.
Explanation:
Given that,
Mass = 275.0 g
Suppose value of spring constant is 6.2 N/m.
We need to calculate the angular frequency
Using formula of angular frequency
![\omega=\sqrt{\dfrac{k}{m}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7Bk%7D%7Bm%7D%7D)
Where, m = mass
k = spring constant
Put the value into the formula
![\omega=\sqrt{\dfrac{6.2}{275.0\times10^{-3}}}](https://tex.z-dn.net/?f=%5Comega%3D%5Csqrt%7B%5Cdfrac%7B6.2%7D%7B275.0%5Ctimes10%5E%7B-3%7D%7D%7D)
![\omega=4.74\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D4.74%5C%20rad%2Fs)
We need to calculate the period of oscillation,
Using formula of time period
![T=\dfrac{2\pi}{\omega}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2%5Cpi%7D%7B%5Comega%7D)
Put the value into the formula
![T=\dfrac{2\pi}{4.74}](https://tex.z-dn.net/?f=T%3D%5Cdfrac%7B2%5Cpi%7D%7B4.74%7D)
![T=1.33\ sec](https://tex.z-dn.net/?f=T%3D1.33%5C%20sec)
Hence, The period of oscillation is 1.33 sec.
Answer:
E) microwave, infrared, visible, ultraviolet
Explanation:
Electromagnetic waves are waves consisting of oscillations of electric and magnetic fields. These fields oscillate in a direction perpendicular to the direction of propagation of the wave, so they are called transverse waves. Electromagnetic waves are the only waves that can travel in a vacuum, since they don't need a medium to propagate.
Electromagnetic waves are classified into 7 different types, according to their different frequency. In order from lowest to highest frequency, we have:
Radio waves
Microwaves
Infrared
Visible light
Ultraviolet
X-rays
Gamma rays
Moreover, for an electromagnetic wave the energy carried is proportional to its frequency:
![E=hf](https://tex.z-dn.net/?f=E%3Dhf)
where h is the Planck constant and f is the frequency. Therefore, the list written above also corresponds to the list of waves from lowest to highest energy. so, the correct answer is
E) microwave, infrared, visible, ultraviolet
Answer:
After the bullet emerges the block moves at 0.99 m/s
Explanation:
Given;
mass of bullet, m₁ = 22 g = 0.022 kg
initial speed of the bullet, u₁ = 240 m/s
final speed of the bullet, v₁ = 150 m/s
mass of block, m₂ = 2.0 kg
initial speed of the block, u₂ = 0
Let the final speed of the block = v₂
Apply principles of conservation of linear momentum;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.022 x 240 + 2 x 0 = 0.022 x 150 + 2v₂
5.28 = 3.3 + 2v₂
5.28 - 3.3 = 2v₂
1.98 = 2v₂
v₂ = 1.98 / 2
v₂ = 0.99 m/s
Therefore, after the bullet emerges the block moves at 0.99 m/s