Answer:
Acceleration is :
a = 2.89 m/s2
Explanation:
Acceleration : It is the change in the velocity of the object per unit time.
The object starts from the rest , so the initial velocity of the object is zero.
Initial velocity , u = 0
Final velocity = 100 km/h
Change the velocity to m/s because[ time unit is in second(9.60 s)]
1 km = 1000 m
1 hour = 60 x 60 sec = 3600 sec
![1km/h=\frac{1000}{3600}m/s](https://tex.z-dn.net/?f=1km%2Fh%3D%5Cfrac%7B1000%7D%7B3600%7Dm%2Fs)
![1km/hr=\frac{5}{18}](https://tex.z-dn.net/?f=1km%2Fhr%3D%5Cfrac%7B5%7D%7B18%7D)
![100km/hr=\frac{5}{18}\times 100](https://tex.z-dn.net/?f=100km%2Fhr%3D%5Cfrac%7B5%7D%7B18%7D%5Ctimes%20100)
![v=\frac{5}{18}\times 100](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B5%7D%7B18%7D%5Ctimes%20100)
v = 27.78 m/s
u = 0 m/s
time = 9.60 s
The acceleration"a" is calculated using :
![a=\frac{v-u}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7Bv-u%7D%7Bt%7D)
![a=\frac{27.78-0}{9.6}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B27.78-0%7D%7B9.6%7D)
![a=\frac{27.78}{9.6}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B27.78%7D%7B9.6%7D)
![a=2.89m/s^{2}](https://tex.z-dn.net/?f=a%3D2.89m%2Fs%5E%7B2%7D)
Answer:
The final temperature of the aluminum is 306°C
Explanation:
Have the follow:
The amount of heat is equal to:
![q=n_{H_{2}O } (100-20)Cx_{H_{2}O } +n_{H_{2}O } H_{vapor} \\q=18.1g*\frac{1mol}{18.02g} *80C*\frac{75.3J}{molC} +18.1g*\frac{1mol}{18.02g} *\frac{40.67kJ}{mol} *\frac{1000J}{1kJ} =46901.3J](https://tex.z-dn.net/?f=q%3Dn_%7BH_%7B2%7DO%20%7D%20%28100-20%29Cx_%7BH_%7B2%7DO%20%7D%20%2Bn_%7BH_%7B2%7DO%20%7D%20H_%7Bvapor%7D%20%5C%5Cq%3D18.1g%2A%5Cfrac%7B1mol%7D%7B18.02g%7D%20%2A80C%2A%5Cfrac%7B75.3J%7D%7BmolC%7D%20%2B18.1g%2A%5Cfrac%7B1mol%7D%7B18.02g%7D%20%2A%5Cfrac%7B40.67kJ%7D%7Bmol%7D%20%2A%5Cfrac%7B1000J%7D%7B1kJ%7D%20%3D46901.3J)
Heat absorbed by the water = heat lost by aluminum
-q = qal
![-q=n_{Al} C_{Al} (T-T_{Al} \\-46901.3J=270g*\frac{1mol}{26.98g} *\frac{24.2J}{molC} (T-500)\\T=306C](https://tex.z-dn.net/?f=-q%3Dn_%7BAl%7D%20C_%7BAl%7D%20%28T-T_%7BAl%7D%20%5C%5C-46901.3J%3D270g%2A%5Cfrac%7B1mol%7D%7B26.98g%7D%20%2A%5Cfrac%7B24.2J%7D%7BmolC%7D%20%28T-500%29%5C%5CT%3D306C)
No, because a natural diamond is a feat of nature and it is amazing how nature made the intricate structure in a diamond. synthetic diamonds are created in laboratory conditions, so it feels less 'amazing' that the diamond was created because each diamond doesn't feel so unique.
However, the molecular structure of both synthetic and natural diamonds are identical, so it is nearly impossible to tell the difference (if you don't know which is which).
Answer:
Average molar bond enthalpy of C-H bond in
is 415.825 kJ/mol.
Explanation:
Reaction: ![CH_{4}(g)\rightarrow C(g)+4H(g)](https://tex.z-dn.net/?f=CH_%7B4%7D%28g%29%5Crightarrow%20C%28g%29%2B4H%28g%29)
Heat of reaction (energy needed to break 4 moles of C-H bond in 1 mol of
) = ![\Delta H^{0}=[1mol\times \Delta H_{f}^{0}(C)_{g}]+[4mol\times \Delta H_{f}^{0}(H)_{g}]-[1mol\times \Delta H_{f}^{0}(CH_{4})_{g}]](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7B0%7D%3D%5B1mol%5Ctimes%20%5CDelta%20H_%7Bf%7D%5E%7B0%7D%28C%29_%7Bg%7D%5D%2B%5B4mol%5Ctimes%20%5CDelta%20H_%7Bf%7D%5E%7B0%7D%28H%29_%7Bg%7D%5D-%5B1mol%5Ctimes%20%5CDelta%20H_%7Bf%7D%5E%7B0%7D%28CH_%7B4%7D%29_%7Bg%7D%5D)
= ![[1mol\times 716.7\frac{kJ}{mol}]+[4mol\times 218.0\frac{kJ}{mol}]-[1mol\times -74.6\frac{kJ}{mol}]=1663.3kJ](https://tex.z-dn.net/?f=%5B1mol%5Ctimes%20716.7%5Cfrac%7BkJ%7D%7Bmol%7D%5D%2B%5B4mol%5Ctimes%20218.0%5Cfrac%7BkJ%7D%7Bmol%7D%5D-%5B1mol%5Ctimes%20-74.6%5Cfrac%7BkJ%7D%7Bmol%7D%5D%3D1663.3kJ)
1 mol of
contain 4 moles of C-H bonds.
So, average molar bond enthalpy of C-H bond in ![CH_{4}](https://tex.z-dn.net/?f=CH_%7B4%7D)
= ![\frac{1663.3}{4}kJ/mol](https://tex.z-dn.net/?f=%5Cfrac%7B1663.3%7D%7B4%7DkJ%2Fmol)
= 415.825 kJ/mol