<span>He discovered that every atom contains a nucleus where all of its positive charge and most of its mass are concentrated</span>
Answer:
![\boxed{\text{(a) 0.00 V; (b) 0.424 V}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B%28a%29%200.00%20V%3B%20%28b%29%200.424%20V%7D%7D)
Explanation:
We must look up the standard reduction potentials for the half-reactions.
<u> ℰ° </u>
Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ⇌ 2Cr³⁺ + 7H₂O 1.36
Cl₂ + 2e⁻ ⇌ 2Cl⁻ 1.35827
2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O 1.195
Fe³⁺ + e⁻ ⇌ Fe²⁺ 0.771
(a) Cr³⁺/Cl₂
We reverse the sign of ℰ° for the oxidation half-reaction. Then we add the two half-reactions and their ℰ° values.
<u> ℰ°/V </u>
2Cr³⁺ + 7H₂O ⇌ Cr₂O₇²⁻ + 14H⁺ + 6e⁻ -1.36
<u>Cl₂ + 2e⁻ ⇌ 2Cl⁻ </u> <u>1.358 27
</u>
2Cr³⁺ + 3Cl₂ + 7H₂O ⇌ Cr₂O₇²⁻ + 6Cl⁻ + 14H⁺ 0.00
(b) Fe²⁺/IO₃⁻
<u> ℰ°/V
</u>
Fe²⁺ ⇌ Fe³⁺ + e⁻ -0.771
<u>2IO₃⁻ + 12H⁺ + 10e⁻ ⇌ I₂ + 6H₂O </u> <u> 1.195
</u>
10Fe²⁺ + 2IO₃⁻ + 12H⁺ ⇌ 10Fe³⁺ + I₂ + 6H₂O 0.424
The ℰ° values for the cells are ![\boxed{\textbf{(a) 0.00 V; (b) 0.424 V}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctextbf%7B%28a%29%200.00%20V%3B%20%28b%29%200.424%20V%7D%7D)
Converting from moles of one compound into moles of another compound in a chemical equation will require the " <u>stoichiometric factor</u>".
The balanced equation's coefficients serve as the foundation for stoichiometric factors, often known as mole ratios, that are employed to compare the moles of one product as well as a reactant to those of another.
A balanced chemical equation's stoichiometry determines the most product that could be produced. A reaction's stoichiometry specifies the proportions of reactants as well as products in a stable chemical equation.
Therefore, converting from moles of one compound into moles of another compound in a chemical equation will require the " <u>stoichiometric factor</u>".
To know more about moles
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It is either netforce or gforce
it may be C. did you get the right answer so you could study it?