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zlopas [31]
3 years ago
6

The formula for europium oxide is Eu203. On the basis of this information, the formula for the chlorate of europium would be exp

ected to be
Chemistry
1 answer:
lina2011 [118]3 years ago
4 0

Answer:

Eu(ClO3)3

Explanation:

The chlorate ion is written as follows, ClO⁻ ₃. We can see from this that the ion is univalent.

From the formula, Eu203, it is easy to see that the europium ion is trivalent.

Hence, when a compound is formed between the europium ion and chlorate ion, the compound will be written as Eu(ClO3)3.

This is so because, when ionic compounds are formed, there is an exchange of valence between the ions in the compound. This gives the final formula of the ionic substance.

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What is 1 mol / 66.04g ​
____ [38]

Answer:

15.142338 mol/kg

Explanation:

(1 mole) / (66.04 grams)

5 0
3 years ago
A solution of an acid could have a pH of __*<br> 3 to 5<br> 6 to 8<br> 9 to 11<br> 12 to 14
sdas [7]

Answer:

3 to 5

Explanation:

The pH scale is from 0 to 14.

Acids have a pH of anything less than 7.

Anything with a pH greater than 7 is considered to be a base.

If a solution has a pH of 7, it is neutral.

3 to 5 is in the range of less than 7, so a solution of an acid can have this pH.

6 to 8 includes less than 7 , 7 and greater than 7, so it is not just in the range of an acid.

9 to 11 and 12 to 14 are both in the range of greater than 7, so they have to be bases.

Therefore, the correct answer is 3 to 5.

4 0
4 years ago
Which of the following is a quantitative observation of the frog?
Nataliya [291]
Quantitative means to count how many of something. The correct answer is B, It has two eyes. Hope this helps
6 0
3 years ago
Read 2 more answers
How many moles of tin atoms are there in 250 grams of tin?
joja [24]

250gTi x (1mol/47.87 [molar mass]) =5.22247 moles

4 0
3 years ago
Consider the reaction:
goldfiish [28.3K]

Answer:

K = Ka/Kb

Explanation:

P(s) + (3/2) Cl₂(g) <-------> PCl₃(g) K = ?

P(s) + (5/2) Cl₂(g) <--------> PCl₅(g) Ka

PCl₃(g) + Cl₂(g) <---------> PCl₅(g) Kb

K = [PCl₃]/ ([P] [Cl₂]⁽³'²⁾)

Ka = [PCl₅]/ ([P] [Cl₂]⁽⁵'²⁾)

Kb = [PCl₅]/ ([PCl₃] [Cl₂])

Since [PCl₅] = [PCl₅]

From the Ka equation,

[PCl₅] = Ka ([P] [Cl₂]⁽⁵'²⁾)

From the Kb equation

[PCl₅] = Kb ([PCl₃] [Cl₂])

Equating them

Ka ([P] [Cl₂]⁽⁵'²⁾) = Kb ([PCl₃] [Cl₂])

(Ka/Kb) = ([PCl₃] [Cl₂]) / ([P] [Cl₂]⁽⁵'²⁾)

(Ka/Kb) = [PCl₃] / ([P] [Cl₂]⁽³'²⁾)

Comparing this with the equation for the overall equilibrium constant

K = Ka/Kb

5 0
3 years ago
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