Need help with these 3 questions pls help me.
2 answers:
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Answer:
hello the required diagram is missing attached to the answer is the required diagram
7.9954 kip.ft
Explanation:
AB = 1550-Ib ( weight acting on AB )
BCD = 190 - Ib ( weight of cage )
169-Ib = weight of man inside cage
Attached is the free hand diagram of the question
calculate distance
= cos 75⁰ =
= 2.59 ft
calculate distance x
= cos 75⁰ =
x = 30 * cos 75⁰ = 7.765 ft
The resultant moment produced by all the weights about point A
∑ Ma = 0
Ma = 1550 * + 190 ( x + 2.5 ) + 169 ( x + 2.5 + 1.75 )
Ma = 1550 * 2.59 + 190 ( 7.765 + 2.5 ) + 169 ( 7.765 + 2.5 + 1.75 )
= 4014.5 + 1950.35 + 2030.535
= 7995.385 ft. Ib ≈ 7.9954 kip.ft
Answer:
T=138 °C
Explanation:
Given that
m = 0.028 kg
Net work output W= 60 KJ
T₂=2T₁
As we know that efficiency of Carnot heat engine given as
η = 0.5
We know that
Qa=heat addition
W= net work output
Qa= 120 KJ
From first law
Qa= W+ Qr
Qr= 120 - 60
Qr= 60 KJ
Qr Is the heat rejection.
Heat rejection per unit mass
Qr=60 / 0.028 = 2142.85 KJ/kg
Qr= 2142.85 KJ/kg
Temperature at which latent heat of steam is 2142.85 KJ/kg will be our answer.
T=138 °C
The temperature corresponding to 2142.85 KJ/kg will be 138 °C.
T=138 °C
Answer:
Explanation:
Given;
For orifice, loss coefficient, K₀ = 10
Diameter, D₀ = 45 mm = 0.045 m
loss coefficient of the orifice, Ko = 10
Diameter of the gate valve, Dy = 1.5D₀ = 1.5 × 0.045 m = 0.0675 m
Total head drop, Δhtotal=25 m
Discharge, Q = 10 l/s = 0.01 m³/s
Now,
the velocity of flow through orifice, Vo = Discharge / area of the orifice
or
Vo =
or
Vo = 6.28 m/s
also,
the velocity of flow through gate valve, = Discharge / area of the orifice
or
=
or
= 2.79 m/s
Now,
the total head drop = head drop at orifice + head drop at gate valve
or
25 m =
where,
is the loss coefficient for the gate valve
on substituting the values, we get
25 m =
or
= 4.898
or