Please explain the theory of Hydrostatic Thrust on a plane Surface
2 answers:
You might be interested in
Answer:
Explanation:
Density is defined as mass ler unit volume, expressed as
Where m is mass, is density and v is the volume. For a sphere, volume is given as
Replacing this into the formula of density then
Given diameter of 2.24 in then the radius is 1.12 in. Substituting 0.82 lb for m then
Answer:
Test code:
>>u=10;
>>g=9.8;
>>q=100;
>>m0=100;
>>vstar=10;
>>tstar=fzero_rocket_example(u, g, q, m0, vstar)
Explanation:
See attached image
Answer:
The power required to cool the water is 1.11Kw.
Hence the correct option is (b).
Explanation:
Power needed to cool down is equal to heat extract from the water.
Given:
Volume of water is 1 liter.
Initial temperature is 100C.
Final temperature is 20C.
Time is 5 minutes.
Take density of water as 100 kg/m3.
Specific heat of water is 4.186 kj/kgK.
Calculation:
Step1
Mass of the water is calculated as follows:
m=1kg
Step2
Amount of heat extraction is calculated as follows:
Q=334880 j.
Step3
Power to cool the water is calculated as follows:
P=1116.26W
or
P=1.11 Kw.
Thus, the power required to cool the water is 1.11Kw.
Hence the correct option is (b).