Answer:
25/29
Step-by-step explanation:
see the attached picture.
Solve the equation `x^{4}+13x^{2}+36=0` for all values of `x`.
1 answer:
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Cancel out the denominators.
(x+5)² + 18 = -30
(x+5)² = -30 - 18
(x+5)² = -48
The equation is impossible, we have a negative number.
There isn't a number that squared gives a negative number (the square is always positive).
√(x+5)² = +/- √-48
x+5 = +/- √-48
IMPOSSIBLE
You can write the result in imaginary numbers
x+5=+/- 4i√3