2 years ago

Physics Help Please!!!

2 answers:

8 0

$v = 13 \frac{m}{s}, \theta = 54^\circ \\ \\ v_{xi} = v*cos \theta \\ v_{yi} = v*sin\theta \\ \\ a_x = 0, a_Y = -10 \frac{m}{s^2} \\ \\ v_{yf} = v_{yi} + a_yt = -v_{yi} \\ t = \frac{2v_{yi}}{a_y}$

liq [111]2 years ago

3 0

The answer is the third graph

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