Answer:
It can go back to it's original shape
Explanation:
Answer:
Explanation:
Velocity at the bottom of height h
= √2gh
deceleration on rough horizontal surface
= μg , μ is coefficient of friction
= .27 x 9.8
= 2.646 m / s²
v² = u² - 2as
0 = 2gh - 2 x 2.646 x 19
h = 2 x 2.646 x 19 / 2 x 9.8
= 5.13 m
The motion of the racers might change from the start because the pressure goes up so all the racer wants is to speed up and win, so when the racer first starts he or she is calm because he's not driving yet and when he or she is on his/hers way to he finish line he/she just wants to win and gets under pressure so he speeds up even more and drifts. Your welcome
Answer:
q = 2.65 10⁻⁶ C
Explanation:
For this exercise we use Coulomb's law
F =
In this case they indicate that the load is of equal magnitude
q₁ = q₂ = q
the force is attractive because the signs of the charges are opposite
F = 
q = 
we calculate
q = 
q = 
Ra 7 10-12
q = 2.65 10⁻⁶ C
