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2 years ago

Physics Help Please!!!

Physics

2 answers:

kolezko [41]2 years ago

8 0

$v = 13 \frac{m}{s}, \theta = 54^\circ \\ \\ v_{xi} = v*cos \theta \\ v_{yi} = v*sin\theta \\ \\ a_x = 0, a_Y = -10 \frac{m}{s^2} \\ \\ v_{yf} = v_{yi} + a_yt = -v_{yi} \\ t = \frac{2v_{yi}}{a_y}$

liq [111]2 years ago

3 0

The answer is the third graph

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2 years ago

A football player with a mass of 88 kg and a speed of 2.0 m/s collides head-on with a player from the opposing team whose mass i

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Answer:

Speed of another player, v₂ = 1.47 m/s

Explanation:

It is given that,

Mass of football player, m₁ = 88 kg

Speed of player, v₁ = 2 m/s

Mass of player of opposing team, m₂ = 120 kg

The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :

$m_1v_1+m_2v_2=(m_1+m_2)V$

V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.

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$v_2=-1.47\ m/s$

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3 years ago

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1 year ago

The Franck-Hertz experiment involved shooting electrons into a low-density gas of mercury atoms and observing discrete amounts o

Anuta_ua [19.1K]

Answer:

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Explanation:

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you can assume that the shot electron excites the electron of the hydrogen atom to the first excited state, that is

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-10.2eV is the energy that the shot electron losses in the excitation of the electron of the hydrogen atom. Hence, the final kinetic energy of the shot electron after it has given -10.2eV of its energy is:

$E_{k}=11.1eV-10.2eV=0.9eV$

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3 years ago