The most logical answer would be C.
M(Na2CO3•10H2O)=23*2+12+16*3+180=286g/mol
So lets take 1 mol of this compound
m(comp)=286 gram
m(H2O)=180 gramm
w(h2o)=180/286=0.6293(62.93%)
Answer 62.93% water
If we are working in a coordinate plane where the endpoints has the coordinates (x1,y1) and (x2,y2) then the midpoint coordinates is found by using the following formula:
midpoint=(x1+x22,y1+y22)
Answer:
rate: K' [H₂O₂]
Explanation:
Every chemical reaction occurs with a determined mechanism. The slow step of the reaction is the rate determining.
According to the reaction:
H₂O₂(aq) → 2 H₂O(l) + O₂(g)
The proposed mechanism (And its rate laws) in the presence of I⁻ is:
Step 1: H₂O₂ + I⁻ → H₂O + OI⁻ (slow) rate₁: K₁ [H₂O₂] [I⁻]
Step 2: H₂O₂ + OI⁻ → H₂O + O₂ (fast) rate₂: K₂ [H₂O₂] [OI⁻]
As the step 1, is the rate-determining, the rate law for the overall reaction is:
<em>rate: K [H₂O₂] [I⁻]</em>
Now, as I⁻ is a catalyst and its concentration over the reaction is constant, it is possible to write:
<em>rate: K' [H₂O₂]</em>
<em>Where K' = K [I⁻]</em>