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Goshia [24]
3 years ago
7

The following two triangles have the same angles, and are similar. What is the ratio of height to base for the triangles?​

Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0
Do you have a picture?
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The primeter of a rectangle is 53 meters. The length is 2.3 meters longer than the width, w. Write and solve an equation to ind
lys-0071 [83]

The perimeter is the total of adding all of the sides together. A rectangle has 2 lengths and 2 widths. The equation would be:

P = 2l + 2w or P = l + l + w + w

Since you know the perimeter, you can plug it into the equation

53 = 2l + 2w

You can divide the 2 on both sides

26.5 = l + w

l = w + 2.3 because the length is 2.3 meters longer/more than the width. You can substitute (w + 2.3) for "l" in the equation. So instead of:

26.5 = l + w

It will be:

26.5 = (w + 2.3) + w

26.5 = w + 2.3 + w

Subtract 2.3 on both sides

24.3 = w + w

24.3 = 2w

Divide 2 on both sides

12.1 = w

The width is 12.1 meters

6 0
3 years ago
Cosx.cosecx + sinx.secx
ElenaW [278]

Answer:

what does this mean

Step-by-step explanation:

huh I don't get it plz explain

8 0
3 years ago
What is the cost of 2.6 pounds at $6.75 per pound?
lisabon 2012 [21]
Since the cost is $6.75 per pound, and we have 2.6 pounds, multiply 6.75•2.6 to find the cost.
It would cost $17.55.
5 0
4 years ago
Can someone please help me:)
Naddika [18.5K]
For a translation 4 units down you would subtract 4 from each y value and 5 units right you would add 5 to each x value.
Your resulting points would be.
A'(-1,1), B'(-1,-2), C'(3,-2), D'(3,2)
4 0
3 years ago
A tank has the shape of an inverted circular cone (point at the bottom) with height 10 feet and radius 4 feet. The tank is full
german

Answer:

Step-by-step explanation:

Given that tank has the shape of inverted circular cone

Height = 10 feet and radius =  4 feet

After water pumped out height = 5 ft

Hence volume of water pumped out = \frac{1}{3} \pi R^2 h-\frac{1}{3} \pi r^2 h'

Here we have r/h is constant always

Hence \frac{r}{h'} =\frac{R}{h} \\r=Rh'/h = 4(5)/10 = 2

Substitute to get volume of water pumped out = \frac{1}{3} \pi (10*16-4*5)=\frac{140\pi}{3}

Mass of water = density x volume = 62.4(\frac{140\pi}{3})\\= 2912\pi lbs

Work done = force x displacement

= mass x accen x displacement

Here acceleration = gravity = 32.2 ft/sec^2

Displaement = height reduced = 5 ft

W=2912(32.2)(5)\pi =468832\pi foot -pound

6 0
3 years ago
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