All categories

3 years ago

What did the discovery of the Cumberland Gap mean for exploration? PLEASE HELP ILL GIVE YOU BRAINLEIST!

Engineering

1 answer:

Flauer [41]3 years ago

6 0

Answer: D. Many more people crossed the mountains and settled between the Appalachians and the Mississippi

Explanation:

It was quite difficult to cross the Appalachian mountains at the time of the American colonies which led to the colonies being confined to the east of it.

This was until the late 1700s when Daniel Boone and a team of explorers heard that a path existed through the Appalachians and had been used by natives for a long time. After discovering this ''gap'' which was then named after an English prince, many more people were able to use it to settle more to the west of the continent.

You might be interested in

Five kilograms of air at 427°C and 600 kPa are contained in a piston–cylinder device. The air expands adiabatically until the pr

son4ous [18]

Answer:

The entropy change of the air is $0.240kJ/kgK$

Explanation:

$T_{1} =427+273K,T_{1} =700K\\P_{1} =600kPa\\P_{2} =100kPa$

$T_{2}$ is unknown

we can apply the following expression to find $T_{2}$

$-w_{out} =mc_{v} (T_{2} -T_{1} )$

$T_{2} =T_{1} -\frac{w_{out } }{mc_{v} }$

now substitute

$T_{2} =700K-\frac{600kJ}{5kg*0.718kJ/kgK} \\T_{2}=533K$

To find entropy change of the air we can apply the ideal gas relationship

Δ $s_{air}$ $=c_{p} ln\frac{T_{2} }{T_{1} } -Rln\frac{P_{2} }{P_{1} }$

Δ $s_{air} =$ $1.005*ln(\frac{533}{700})-0.287* in(\frac{100}{600} )$

Δ $s_{air} =0.240kJ/kgK$

4 0

2 years ago

The complex power of a load is 10-10j VA. What component should be added in parallel with the load so that the new load has a un

Korolek [52]

Need points bdjdjdhdhd

7 0

3 years ago

Bending is defined as? A. the application of a load tending to distort a member in one direction. B. the application of opposing

amm1812

Hi how are you today

4 0

2 years ago

A two-dimensional flow field described by

Oduvanchick [21]

Answer:

the answer is

Explanation:

<h2> We now focus on purely two-dimensional flows, in which the velocity takes the form </h2><h2>u(x, y, t) = u(x, y, t)i + v(x, y, t)j. (2.1) </h2><h2>With the velocity given by (2.1), the vorticity takes the form </h2><h2>ω = ∇ × u = </h2><h2> </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y </h2><h2>k. (2.2) </h2><h2>We assume throughout that the flow is irrotational, i.e. that ∇ × u ≡ 0 and hence </h2><h2>∂v </h2><h2>∂x − </h2><h2>∂u </h2><h2>∂y = 0. (2.3) </h2><h2>We have already shown in Section 1 that this condition implies the existence of a velocity </h2><h2>potential φ such that u ≡ ∇φ, that is </h2><h2>u = </h2><h2>∂φ </h2><h2>∂x, v = </h2><h2>∂φ </h2><h2>∂y . (2.4) </h2><h2>We also recall the definition of φ as </h2><h2>φ(x, y, t) = φ0(t) + Z x </h2><h2>0 </h2><h2>u · dx = φ0(t) + Z x </h2><h2>0 </h2><h2>(u dx + v dy), (2.5) </h2><h2>where the scalar function φ0(t) is arbitrary, and the value of φ(x, y, t) is independent </h2><h2>of the integration path chosen to join the origin 0 to the point x = (x, y). This fact is </h2><h2>even easier to establish when we restrict our attention to two dimensions. If we consider </h2><h2>two alternative paths, whose union forms a simple closed contour C in the (x, y)-plane, </h2><h2>Green’s Theorem implies that </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2></h2><h2></h2>

5 0

3 years ago

How to build a robot

Anuta_ua [19.1K]

Seriously? Ok

first, get some good quality metal, preferably aluminum, if you want to avoid rust.

build in the the shape of a robot, you can use a doll to help you if you are a beginner, but feel free to shape it the a Star Wars Character!

create an AI (now you said robot not AI) and fix everything up.

7 0

3 years ago