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Whitepunk [10]
3 years ago
11

How will the proposed study contribute to your career?*(quantity Surveying​

Engineering
1 answer:
Flauer [41]3 years ago
5 0

Answer:

PROPOSED STUDY CONTRIBUTES TO YOUR CAREER. Proposed study is essential for career growth. It contributes to our career in a great way. It <u>enhances leadership skills</u> and polish our skills making us more competent. It expand our horizons and opportunities. It gives us better understanding of things. We become able of developing professional relationships with our students as well as development sector which helps in future projects.

Hope this help!:)

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In electric heaters, electrical energy is converted to potential energy. a)-True b)-false?
son4ous [18]

Answer:

False

Explanation:

In electric heater electric energy is converted into heat energy. In heater wires are present which have resistance and current is flow in heater when we connect the heater to supply.

And we know that whenever current is flow in any resistance then heat is produced so in electric heaters electric energy is converted into heat energy

So this is a false statement

8 0
3 years ago
How long should the shafts remain in the furnace to achieve a desired centerline temperature of 800K? 2) Determine the temperatu
Phantasy [73]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

6 0
3 years ago
Random question, does anyone here use Lego, do not answer unless that is a yes
Sophie [7]

Answer:

yes i have 2 huge bins of it

Explanation:

8 0
3 years ago
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Consider air entering a heated duct at P1 = 1 atm and T1 = 288 K. Ignore the effect of friction. Calculate the amount of heat pe
Ne4ueva [31]

Answer:

The solution for the given problem is done below.

Explanation:

M1 = 2.0

\frac{p1}{p*} = 0.3636

\frac{T1}{T*} = 0.5289

\frac{T01}{T0*} = 0.7934

Isentropic Flow Chart:  M1 = 2.0 , \frac{T01}{T1} = 1.8

T1 = \frac{1}{0.7934} (1.8)(288K) = 653.4 K.

In order to choke the flow at the exit (M2=1), the above T0* must be stagnation temperature at the exit.

At the inlet,

T02= \frac{T02}{T1}T1 = (1.8)(288K) = 518.4 K.

Q= Cp(T02-T01) = \frac{1.4(287 J / (Kg.K)}{1.4-1}(653.4-518.4)K = 135.7*10^{3} J/Kg.

5 0
3 years ago
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All aspects of the Kirby-Bauer test are standardized to assure reliability. What might be the consequence of pouring the plates
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it would affect the distance the antiantibodies diffuse from the disk

Explanation:

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