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3 years ago

What is the derivation for Newtons Law of universal gravitation?

Physics

1 answer:

Ber [7]3 years ago

6 0

Answer:

In symbols, the magnitude of the attractive force F is equal to G (the gravitational constant, a number the size of which depends on the system of units used and which is a universal constant) multiplied by the product of the masses (m1 and m2) and divided by the square

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Mework

S_A_V [24]

The force applied by the student is 75 N

Explanation:

We can solve this problem by using Newton's second law, which states that the force applied on an object is equal to the product between the mass of the object and its acceleration:

$F=ma$

where

F is the force applied

m is the mass of the object

a is the acceleration

In this problem,

m = 50 kg

$a=1.5 m/s^2$

Substituting, we find the force applied by the student:

$F=(50)(1.5)=75 N$

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

8 0

3 years ago

A silica-rich igneous rock that has large crystals and makes up much of the continental crust is ________

Oxana [17]

A silica-rich igneous rock that has large crystals and makes up much of the continental crust is called granite. These rocks are usually pink, gray or white in color depending on the minerals found on the rock. Generally, granite would have a range of 20% to 60% by volume of quartz and a minimum of 35% feldspar. This rock is a result from volcanic arcs and from the collision of continental masses. Due to its abundance, it has been used in a number of applications. It is used as an aggregate and filler in roading and construction industries. It is also cut and polished to be used in foyers, building facings, bench counters and tops.

6 0

3 years ago

A magnetic field perpendicular to the plane of a wire loop with an area of 0.40 m^2 decreases by 0.2 T in 10^-3 sec. What is the

SVETLANKA909090 [29]

Answer:

Induced EMF in the loop is 80 volts.

Explanation:

Given that,

Magnetic field, $\Delta B=0.2\ T$

Time, $\Delta t=10^{-3}\ s$

Area of the loop, $A=0.4\ m^2$

We need to find the magnitude of the average value of the emf induced in the loop. Due to change in magnetic field, an emf is induced in the loop which is given by :

$\epsilon_o=\dfrac{\Delta\phi}{dt}$

$\epsilon=A\dfrac{\Delta B}{\Delta t}$

$\epsilon=0.4\times \dfrac{0.2}{10^{-3}}$

$\epsilon=80\ V$

So, the value of induced emf is 80 V. Hence, this is the required solution.

5 0

3 years ago

Suppose that you have a spring gun that you use to launch a small metal ball. You try the first two settings of the gun. The fir

Ivan

Answer:

The distance s of how far the ball will go at the highest setting = 2.25m

Explanation:

Let consider x to be the representative of the compression and the distance to be s

Recall that:

$\dfrac{1}{2}\times K \times x^2 = mgs +c$

By cross multiplying

$K \times x^2 = 2(mgs +c)$

$K \times x^2 = 2\times 9.81(ms) +2c$

$K \times x^2 = 19.62(ms) +2c$

$x^2 = A \times s+B$

Thus, for the first setting

x = 1 , s = 0.25

for the second setting

x = 2, s = 1

1 = 0.25A + B --- (1)

4 = A + B ----- (2)

From (1); let B = 1 - 0.25A and substitute it into (2)

4 = A + 1 - 0.25 A

4 - 1 = A - 0.25 A

3 = 0.75 A

A = 3/0.75

A = 4

From (2)

4 = A + B

4 = 4 + B

B = 4 - 4

B = 0

Therefore, for the highest setting, where x = 3

Then :

$x^2 = A \times s+B$ will be:

3² = 4s + 0

9 = 4s

s = 9/4

s = 2.25 m

∴

The distance s of how far the ball will go at the highest setting = 2.25m

6 0

4 years ago

What is the period of a wave that travels through a spring at 2.5 m/s and has a wavelength of 1.3 meters?

ruslelena [56]

Answer:

v=(1/f) ×λ

(1/f)= v/λ

(1/f)= 2.5 ÷ 1.3

(1/f)= 1.92 seconds

T = 1.92 seconds

Explanation:

period= 1÷ frequency

T=1/f

7 0

2 years ago

What is the derivation for Newtons Law of universal gravitation?​

What is the derivation for Newtons Law of universal gravitation?