Question

A magnetic field perpendicular to the plane of a wire loop with an area of 0.40 m^2 decreases by 0.2 T in 10^-3 sec. What is the magnitude of the average value of the emf induced in the loop? (a) 80 V (b) 60 V (c) 40 V (d) 20 V (c) 10 V

Answer 1

Answer:

Induced EMF in the loop is 80 volts.

Explanation:

Given that,

Magnetic field, $\Delta B=0.2\ T$

Time, $\Delta t=10^{-3}\ s$

Area of the loop, $A=0.4\ m^2$

We need to find the magnitude of the average value of the emf induced in the loop. Due to change in magnetic field, an emf is induced in the loop which is given by :

$\epsilon_o=\dfrac{\Delta\phi}{dt}$

$\epsilon=A\dfrac{\Delta B}{\Delta t}$

$\epsilon=0.4\times \dfrac{0.2}{10^{-3}}$

$\epsilon=80\ V$

So, the value of induced emf is 80 V. Hence, this is the required solution.