To solve this problem, we use the equation:
<span>d = (v^2 - v0^2) /
2a</span>
where,
d = distance of collapse
v0 = initial velocity = 101 km / h = 28.06 m / s
v = final velocity = 0
a = acceleration = - 300 m / s^2
d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)
<span>d = 1.31 m</span>
when object goes under acceleration
c).its velocity always increases
<h3><u>Additional</u><u> </u><u>information</u><u>:</u><u>-</u></h3>
★ Acceleration: Rate of increase in velocity.
★ Velocity: Distance travelled by a body per unit time in given direction is called velocity .
Answer:
<em>The distance covered by comet is </em>
Explanation:
Speed is defined as the rate of change of distance with time. It is given by the equation speed= 
Thus distance= 
In this problem it is given that speed of comet= 
time travelled by the comet= 4 hours
Thus distance= 
= 
= 
Answer:
(a) the force is 8.876 N
(b) the magnitude of each charge is 4.085 μC
Explanation:
Part (a)
Given;
coulomb's constant, K = 8.99 x 10⁹ N.m²/C²
distance between two charges, r = 10 cm = 0.1 m
force between the two charges, F = 15 N
when the distance between the charges changes to 13 cm (0.13 m)
force between the two charges, F = ?
Apply Coulomb's law;

Part (b)
the magnitude of each charge, if they have equal magnitude

where;
F is the force between the charges
K is Coulomb's constant
Q is the charge
r is the distance between the charges
