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Sedbober [7]
2 years ago
13

A 1 kg pistol, initially at rest, shoots a bullet with a mass of 2.5g. After

Physics
1 answer:
Allisa [31]2 years ago
6 0

Answer:

Use the principle of momentum

Initial momentum = final momentum

Momentum formula = Mass * Velocity

Explanation:

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Two identical balls collide one was initially at rest. after the collision one of the balls has a velocity of 3 m/s south. the o
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Two identical balls collide<span> head on. The </span>initial velocity<span> of </span>one<span> is 0.75 </span>m/s<span> east, while that of the </span>other one<span> is 0.43 </span>m/s west<span>.</span>
4 0
3 years ago
What is the speed of a bobsled whose distance-time graph indicates that it traveled 122m in 27s?
Stolb23 [73]
Speed = distance/time
speed= 122÷27=4.52m/s (3sf)
7 0
3 years ago
In this problem, you will calculate the location of the center of mass for the Earth-Moon system, and then you will calculate th
Radda [10]

Answer:

a) Option D is correct.

The center of mass between the Eartg and the moon is inside the Earth.

Explanation:

Given,

Mass of the moon = (7.35×10²²) kg

Mass of the Earth = (6.00×10²⁴) kg

Mass of the Sun = (2.00×10³⁰) kg

Distance between the Earth and the moon = (3.80×10⁵) km

Distance between the Earth and the Sun = (1.50×10⁸) km

With the assumption that all.of the bodies being considered are on the same straight line on the x-axis,

Note that Centre of mass is given as

C.M = (Σmx)/(Σm)

For the Earth-moon system, let the earth be x=0, then the moon is at x = (3.80 × 10 5) km away.

C.M = (Σmx)/(Σm)

Σmx = (6.00×10²⁴)) × (0) + (7.35×10²²) × (3.80×10⁵) = (2.793 × 10²⁸) kg.km

Σm = (6.00×10²⁴) + (7.35×10²²) = (6.0735 × 10²⁴) kg

CM = (2.793 × 10²⁸) ÷ (6.0735 × 10²⁴)

CM = (4.60 × 10³) km = 4600 km

This means the centre of mass is 4600 km from the Earth.

The Earth's radius = 6378 km

Hence, the centre if mass is inside the Earth.

Hope this Helps!!!

8 0
3 years ago
Un globo de aire caliente tiene un volumen de 560 mL a la presión atmosférica normal y una temperatura del aire de 400 ºC. Cuand
dalvyx [7]

Explanation:

charles law V1/T1 =V2/T2

560 x 673 =V2/973

376880 = V2/973

V2 = 376880 x 973 = 366704240mL

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3 years ago
How many quantum numbers are used to describe the energy state of an electron in an atom
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We have Four (4). quantum number used in description of the energy state of an electron.
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