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sukhopar [10]
2 years ago
8

Please help! I need it.

Mathematics
1 answer:
IrinaVladis [17]2 years ago
6 0

Answer:

C

Step-by-step explanation:

3 - (-12) = 15

6 + (-24) = (-18)

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Plz help me on this question i dont get angles very well
PSYCHO15rus [73]

Answer:

Someone also posted the same question as yours.

It seems that it's a H.W or a quiz.

8 0
2 years ago
Keshawn is planning to drive from City X to City Y. The scale drawing below shows the distance between the two cities with a sca
Zarrin [17]

Answer:

14 m actural sif 124075n

Step-by-step explanation:

8 0
2 years ago
The distance of the line 2x-3y=4 from the point(1,1) in the direction of the line x y=1 is
Temka [501]
The required line is parallel to line x + y = 1 and passes through point (1, 1).
For parallel lines, slope is equal.
x + y = 1
y = -x + 1 => slope is -1
Line passing though point (1, 1) with slope = -1 is given by y - 1 = -(x - 1)
y - 1 = -x + 1
y + x = 1 + 1 = 2
i.e. Equation of the required lin is x + y = 2

Required distance is the distance between point (1, 1) and the point of intersection of lines x + y = 2 and 2x - 3y = 4.
x + y = 2 . . . (1)
2x - 3y = 4 . . . (2)

(1) x 2 => 2x + 2y = 4 . . . (3)

(2) - (3) => -5y = 0 => y = 0
From (1), x + 0 = 2 => x = 2.
i.e. the point of intersection of lines x + y = 2 and 2x - 3y = 4 is (2, 0).

Required distance is
d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ =\sqrt{(0 - 1)^2+(2-1)^2}=\sqrt{(-1)^2+1^2}  \\ =\sqrt{1+1}  \\ = \sqrt{2}
8 0
3 years ago
Unit 3 Homework: Complete, save and submit in the Assignment Folder to receive 15 points.
vivado [14]

Answer:

your not getting the answer report if u want to :)

Step-by-step explanation:

4 0
2 years ago
If a trangle is acute , then all of its exterior angles will be acute?
snow_tiger [21]
Yes of course! Lol. You are funny young one.

4 0
3 years ago
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