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3 years ago

What is the equilibrium constant expression for the reaction 2no2 --> 2no + o2?

Chemistry

1 answer:

UkoKoshka [18]3 years ago

4 0

Equilibrium constants use the following set up

Keq= [products]/[reactants]

i have attached a drawing with the expression

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Salt is dissolved in a flask of tap water. Distilling the mixture causes the salt to separate from the water. Which type of ener

Alik [6]

Heat energy is required.
In distillation, the solution is first heated, where heat energy is required, such as using a bunsen burner.
When the solution is heated, the water may reach its boiling point and evaporate. However, salt does not. When water molecules evaporates, it travels through a condenser that cools it down into liquid again. Therefore we get pure water. Salt is also obtained in the original beaker.
Therefore to first start this process, heat energy is required.

6 0

3 years ago

Read 2 more answers

If the temperature on 244 mL of a gas is changed to 488 mL and 6 atm, at constant

Fittoniya [83]

Answer:

Explanation:

To find the initial pressure we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the initial pressure

$P_1 = \frac{P_2V_2}{V_1} \\$

From the question we have

$P_1 = \frac{488 \times 6}{244} = \frac{2928}{244} \\$

We have the final answer as

Hope this helps you

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3 years ago

Why the bonds between nonmentals tend to be covalent

natita [175]

Ionic bonds form when a nonmetal and a metal exchange electrons, while covalent bonds form when electrons are shared between two nonmetals. An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions.

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3 years ago

What is the most abundant metalloid in the universe

yan [13]

The answer is Scicillion

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3 years ago

The ksp of yttrium fluoride, yf3, is 8.62 × 10-21. calculate the molar solubility of this compound.

motikmotik

Answer:

The molar solubility of YF₃ is 4.23 × 10⁻⁶ M.

Explanation:

In order to calculate the molar solubility of YF₃ we will use an ICE chart. We identify 3 stages: Initial, Change and Equilibrium and we complete each row with the concentration of change of concentration. Let's consider the solubilization of YF₃.

YF₃(s) ⇄ Y³⁺(aq) + 3 F⁻(aq)

I 0 0

C +S +3S

E S 3S

The solubility product (Ksp) is:

Ksp = [Y³⁺].[F⁻]³= S . (3S)³ = 27 S⁴

$S=\sqrt[4]{Ksp/27} =\sqrt[4]{8.62 \times 10^{-21} /27}=4.23 \times 10^{-6}M$

6 0

4 years ago