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Liono4ka [1.6K]

3 years ago

9

An ostrich runs north in a straight line for 21 meters. She then turns around and runs 25 meters back toward her nest (south) on

the same path. What is her displacement? please explain

1 answer:

drek231 [11]3 years ago

6 0

The ostrich runs 21 N then goes back by 25 S

The displacement is -4 S

21 - 25 = -4

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Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom

Triss [41]

Ok the ML (the 3rd number) is not legit because the ML value can only be from -L to L (the second value)

7 0

3 years ago

An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit

Anon25 [30]

<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol

<u>Explanation:</u>

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of triprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL$

Putting values in above equation, we get:

$3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol$

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

7 0

2 years ago

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miss Akunina [59]

PH + pOH = 14

pH
= 14 - pOH
= 14 - 11
= 3

pH = 3
- lg [H+] = 3
[H+]
= 0.001
= [HNO3]
= 1 x 10-3 M

8 0

2 years ago

Cl2 and N2 react according to the following equation 3Cl2(g) + N2(g) rightarrow 2NCl3(g) If 4 L of a stoichiometric mixture of c

melamori03 [73]

Answer:

Volume of NCl3 is 3L

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3L of chlorine and 1L of nitrogen produce 2L of Nitrogen trichloride.

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2 years ago

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vodomira [7]

B. 8

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5 0

2 years ago

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